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When comparing two 18 digit ints, it's possible to get a true result even when the digits are different.
Example: 2362747255796852672 is equal to 2362747255796852700. I can vary the numbers a bit and still get the same result, e.g. adding multiple zeros to both numbers, varying the three last digits somewhat.
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Hi @henrikj ,
Because it treats both the numbers as 2.36275E+18, it's by design for a number format.
As a workaroud, you can modify the formula to:
Best regards,
Community Support Team_yanjiang