Get certified for free when you join Fabric Data Days 2026 and dive into Fabric, Power BI, SQL, AI, and other essential data skills.
Join nowData Days is here! Join us now for 60+ days of learning, challenges, and connection. Learn more
Hi there,
I have to change this into integers and add zeros according to Billion and million.
any help or suggestions are appreciated.
Thank you
Solved! Go to Solution.
Hi, @Burhan_Jiru
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45W0jbWMzR1UorVATItDcx9wSxdc2M9IyAzFgA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t]),
power = [M = 6, B = 9],
f = (t as text) => Number.From(Text.TrimEnd(t, Record.FieldNames(power))) * Number.Power(10, Record.Field(power, Text.End(t, 1))),
s = Table.TransformColumns(Source, {"Column1", f})
in
s
let
Sci = [M = "e6", B = "e9"],
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45W0jbWMzR1UorVATItDcx9wSxdc2M9IwjT0EjP2EQpNhYA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t]),
Transformed = Table.AddColumn(Source, "Num", each Expression.Evaluate(Text.Select([Column1], {"0".."9","-","."}) & (try Record.Field(Sci, Text.End([Column1],1)) otherwise "")))
in
Transformed
| Thanks to the great efforts by MS engineers to simplify syntax of DAX! Most beginners are SUCCESSFULLY MISLED to think that they could easily master DAX; but it turns out that the intricacy of the most frequently used RANKX() is still way beyond their comprehension! |
DAX is simple, but NOT EASY! |
or this
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45W0jbWMzR1UorVATItDcx9wSxdc2M9IyAzFgA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t]),
power = [M = "e6", B = "e9"],
f = (t as text) =>
Number.From(
Text.Remove(t, Record.FieldNames(power)) & Record.Field(power, Text.End(t, 1))
),
s = Table.TransformColumns(Source, {"Column1", f})
in
s
Hello,
thank you for your help.
I am adding a custom column with this m code but getting a table instead of values.
then replace "s" line with
s = Table.AddColumn(Source, "Amount", each f([Column1]))
This adds a new column "Amount" to table Source.
Hi, @Burhan_Jiru
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45W0jbWMzR1UorVATItDcx9wSxdc2M9IyAzFgA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t]),
power = [M = 6, B = 9],
f = (t as text) => Number.From(Text.TrimEnd(t, Record.FieldNames(power))) * Number.Power(10, Record.Field(power, Text.End(t, 1))),
s = Table.TransformColumns(Source, {"Column1", f})
in
s
Don't miss out on Data Days, June 15 through August 7. Learn Fabric, Power BI, SQL, AI and more.
Check out the May 2026 Power BI update to learn about new features.
| User | Count |
|---|---|
| 5 | |
| 4 | |
| 3 | |
| 2 | |
| 1 |
| User | Count |
|---|---|
| 11 | |
| 11 | |
| 5 | |
| 4 | |
| 3 |