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dfs29
Helper I
Helper I

divide function

Hello , 

 

I am trying to divide "_Total (hm)" with "_Total_total" but it dosn't work because total type is text not number 

So I tried to convert "_Total (hm)" to second and try again but failed ...

Is there someone to help me please ? 

 

dfs29_0-1665656189582.png

 

 

 

 

1 ACCEPTED SOLUTION
v-jianboli-msft
Community Support
Community Support

Hi @dfs29 ,

 

If they are text type, please try:

hm = 
var _hh = VALUE(LEFT(MAX('Table'[_Total (hm)]),(FIND(":",MAX('Table'[_Total (hm)]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total (hm)]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total (hm)]),2))
return _hh*60*60+_mm*60+_ss

total = 
var _hh = VALUE(LEFT(MAX('Table'[_Total_total]),(FIND(":",MAX('Table'[_Total_total]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total_total]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total_total]),2))
return _hh*60*60+_mm*60+_ss

Percentage = DIVIDE([hm],[total]) 

Final output:

vjianbolimsft_1-1665713589633.png

 

Best Regards,

Jianbo Li

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

4 REPLIES 4
v-jianboli-msft
Community Support
Community Support

Hi @dfs29 ,

 

This is caused by the context of the meaure.

I have modified the measure, please try:

 

Percentage =
VAR _a =
    ADDCOLUMNS (
        'Table',
        "hm",
            VALUE (
                LEFT ( 'Table'[_Total (hm)], ( FIND ( ":", 'Table'[_Total (hm)] ) - 1 ) )
            ) * 60 * 60
                + VALUE ( LEFT ( RIGHT ( 'Table'[_Total (hm)], 5 ), 2 ) ) * 60
                + VALUE ( RIGHT ( 'Table'[_Total (hm)], 2 ) ),
        "total",
            VALUE (
                LEFT ( 'Table'[_Total_total], ( FIND ( ":", 'Table'[_Total_total] ) - 1 ) )
            ) * 60 * 60
                + VALUE ( LEFT ( RIGHT ( 'Table'[_Total_total], 5 ), 2 ) ) * 60
                + VALUE ( RIGHT ( 'Table'[_Total_total], 2 ) )
    )
RETURN
    DIVIDE ( SUMX ( _a, [hm] ), MAXX ( _a, [total] ) )

 

Final output:

vjianbolimsft_0-1665972109699.png

Best Regards,

Jianbo Li

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

 

thanks, but I don t know why when I use only one row with my exemple the percentage is wrong : 

 

dfs29_2-1666012330077.pngIt souhld be  100 % here and not 300 %

 

this how I calculate 

Percentage =
VAR _a =
    ADDCOLUMNS (
        'Table',
        "hm",
            VALUE (
                LEFT ( ACT_activite[_Total (hm)], ( FIND ( ":", ACT_activite[_Total (hm)] ) - 1 ) )
            ) * 60 * 60
                + VALUE ( LEFT ( RIGHT ( ACT_activite[_Total (hm)], 5 ), 2 ) ) * 60
                + VALUE ( RIGHT ( ACT_activite[_Total (hm)], 2 ) ),
        "total",
            VALUE (
                LEFT ( 'ACT_activite'[_Total_total], ( FIND ( ":", ACT_activite[_Total_total] ) - 1 ) )
            ) * 60 * 60
                + VALUE ( LEFT ( RIGHT ( ACT_activite[_Total_total], 5 ), 2 ) ) * 60
                + VALUE ( RIGHT ( ACT_activite[_Total (hm)], 2 ) )
    )
RETURN
    DIVIDE ( SUMX ( _a, [hm] ), MAXX ( _a, [total] ) )

 

dfs29
Helper I
Helper I

Hi @v-jianboli-msft 

 

First , thank you so much for your help !!!!

And I have question why the total is false it should be 100% not 10.76% do yuou know why ? 

 

Thanks 🙂

v-jianboli-msft
Community Support
Community Support

Hi @dfs29 ,

 

If they are text type, please try:

hm = 
var _hh = VALUE(LEFT(MAX('Table'[_Total (hm)]),(FIND(":",MAX('Table'[_Total (hm)]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total (hm)]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total (hm)]),2))
return _hh*60*60+_mm*60+_ss

total = 
var _hh = VALUE(LEFT(MAX('Table'[_Total_total]),(FIND(":",MAX('Table'[_Total_total]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total_total]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total_total]),2))
return _hh*60*60+_mm*60+_ss

Percentage = DIVIDE([hm],[total]) 

Final output:

vjianbolimsft_1-1665713589633.png

 

Best Regards,

Jianbo Li

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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