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Hello ,
I am trying to divide "_Total (hm)" with "_Total_total" but it dosn't work because total type is text not number
So I tried to convert "_Total (hm)" to second and try again but failed ...
Is there someone to help me please ?
Solved! Go to Solution.
Hi @dfs29 ,
If they are text type, please try:
hm =
var _hh = VALUE(LEFT(MAX('Table'[_Total (hm)]),(FIND(":",MAX('Table'[_Total (hm)]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total (hm)]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total (hm)]),2))
return _hh*60*60+_mm*60+_ss
total =
var _hh = VALUE(LEFT(MAX('Table'[_Total_total]),(FIND(":",MAX('Table'[_Total_total]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total_total]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total_total]),2))
return _hh*60*60+_mm*60+_ss
Percentage = DIVIDE([hm],[total])
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @dfs29 ,
This is caused by the context of the meaure.
I have modified the measure, please try:
Percentage =
VAR _a =
ADDCOLUMNS (
'Table',
"hm",
VALUE (
LEFT ( 'Table'[_Total (hm)], ( FIND ( ":", 'Table'[_Total (hm)] ) - 1 ) )
) * 60 * 60
+ VALUE ( LEFT ( RIGHT ( 'Table'[_Total (hm)], 5 ), 2 ) ) * 60
+ VALUE ( RIGHT ( 'Table'[_Total (hm)], 2 ) ),
"total",
VALUE (
LEFT ( 'Table'[_Total_total], ( FIND ( ":", 'Table'[_Total_total] ) - 1 ) )
) * 60 * 60
+ VALUE ( LEFT ( RIGHT ( 'Table'[_Total_total], 5 ), 2 ) ) * 60
+ VALUE ( RIGHT ( 'Table'[_Total_total], 2 ) )
)
RETURN
DIVIDE ( SUMX ( _a, [hm] ), MAXX ( _a, [total] ) )
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
thanks, but I don t know why when I use only one row with my exemple the percentage is wrong :
It souhld be 100 % here and not 300 %
this how I calculate
First , thank you so much for your help !!!!
And I have question why the total is false it should be 100% not 10.76% do yuou know why ?
Thanks 🙂
Hi @dfs29 ,
If they are text type, please try:
hm =
var _hh = VALUE(LEFT(MAX('Table'[_Total (hm)]),(FIND(":",MAX('Table'[_Total (hm)]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total (hm)]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total (hm)]),2))
return _hh*60*60+_mm*60+_ss
total =
var _hh = VALUE(LEFT(MAX('Table'[_Total_total]),(FIND(":",MAX('Table'[_Total_total]))-1)))
var _mm = VALUE(LEFT(RIGHT(MAX('Table'[_Total_total]),5),2))
var _ss = VALUE(RIGHT(MAX('Table'[_Total_total]),2))
return _hh*60*60+_mm*60+_ss
Percentage = DIVIDE([hm],[total])
Final output:
Best Regards,
Jianbo Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
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