The ultimate Fabric, Power BI, SQL, and AI community-led learning event. Save €200 with code FABCOMM.
Get registeredEnhance your career with this limited time 50% discount on Fabric and Power BI exams. Ends September 15. Request your voucher.
Hello, please can someone explain why these two measures produce different results (something to do with the AND/OR but I don't understand why these would differ)? (I am reposting this as I made an error in my original post)
measure 1 check (no.) =
CALCULATE (
COUNT ( fct_core[colour] ),
fct_core[type] = 1
|| fct_core[type] = 2
|| fct_core[type] = 3
&& fct_core[colour] = 5
|| fct_core[colour] = 6
|| fct_core[colour] = 7
|| fct_core[colour] = 8
)
and:
measure 2 check (no.) =
CALCULATE (
COUNT ( fct_core[colour] ),
fct_core[type] >= 1
&& fct_core[type] <= 3
&& fct_core[colour] = 5
|| fct_core[colour] = 6
|| fct_core[colour] = 7
|| fct_core[colour] = 8
)
thanks,
A
Solved! Go to Solution.
Suppose you have type 2 and color 4. Then measure 1 would count it but not measure 2.
Note that your logical combination
T1 || T2 || T3 && C5 || C6 || C7 || C8
is equivalent to
T1 || T2 || (T3 && C5) || C6 || C7 || C8
not as I think you intended
(T1 || T2 || T3) && (C5 || C6 || C7 || C8)
I'd rewrite the measure as
check (no.) =
CALCULATE (
COUNT ( fct_core[colour] ),
fct_core[type] IN { 1, 2, 3 },
fct_core[colour] IN { 5, 6, 7, 8 }
)
Suppose you have type 2 and color 4. Then measure 1 would count it but not measure 2.
Note that your logical combination
T1 || T2 || T3 && C5 || C6 || C7 || C8
is equivalent to
T1 || T2 || (T3 && C5) || C6 || C7 || C8
not as I think you intended
(T1 || T2 || T3) && (C5 || C6 || C7 || C8)
I'd rewrite the measure as
check (no.) =
CALCULATE (
COUNT ( fct_core[colour] ),
fct_core[type] IN { 1, 2, 3 },
fct_core[colour] IN { 5, 6, 7, 8 }
)
That is really helpful, thanks Alexis and for stackoverflow too!