Forum Discussion
Split column then pivot back
- 3 years ago
NewStep=#table(Table.ColumnNames(PreviousStepName),List.TransformMany(Table.ToRows(PreviousStepName),each List.Zip(List.Transform(List.Skip(_,2),each Text.Split(_,"/"))),(x,y)=>List.FirstN(x,2)&y))
As I only provided a sample of the data in my original post, I've gone on to attempt to use it with live data and there are some cells (in other columns) that are blank (null) in the query and that is causing it to error. Is there a way I can work around this without having to get rid of the null values. For example, there will not always be a job number assigned so the cell will be blank..
Thanks again for the start on the code.
NewStep=#table(Table.ColumnNames(PreviousStepName),List.TransformMany(Table.ToRows(PreviousStepName),each List.Zip(List.Transform(List.Skip(_,2),each if _=null then {null} else Text.Split(_,"/"))),(x,y)=>List.FirstN(x,2)&y))