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SuzieKidd
Frequent Visitor

SQL to DAX

How do I write the following SQL in DAX please

 

DATEADD(s,-1,DATEADD(mm,0,DATEADD(mm,DATEDIFF(mm,0,GETDATE()),0)))

 

Thank you

1 ACCEPTED SOLUTION
smpa01
Super User
Super User

@SuzieKidd 

 

 

select DATEADD(s,-1,DATEADD(mm,0,DATEADD(mm,DATEDIFF(mm,0,DATEFROMPARTS(2023,8,15)),0)))

 

 

returns

 

 

2023-07-31 23:59:59.000

 

 

You need DAX like this

 

 

Column = 
VAR dt = DATE(2023,8,15)
VAR yr = YEAR(dt)
VAR mo = MONTH(dt)
VAR date2 = DATE(yr,mo,1)
RETURN (date2-1)+0.99999

or 

Column = 
VAR dt = DATE(2023,8,15)
VAR yr = YEAR(dt)
VAR mo = MONTH(dt)
VAR date2 = DATE(yr,mo,1)
RETURN (date2-1)+CONVERT(TIME(23,59,59),DOUBLE)

 

 

 

smpa01_0-1675790584176.png

replace GETTODAY() with TODAY() in DAX

Why 0.99999 works here I have no idea,

@AlexisOlson  do you know why it works? Can we achieve that part through a calculation rather than hardcoding

 

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5 REPLIES 5
smpa01
Super User
Super User

@SuzieKidd 

 

 

select DATEADD(s,-1,DATEADD(mm,0,DATEADD(mm,DATEDIFF(mm,0,DATEFROMPARTS(2023,8,15)),0)))

 

 

returns

 

 

2023-07-31 23:59:59.000

 

 

You need DAX like this

 

 

Column = 
VAR dt = DATE(2023,8,15)
VAR yr = YEAR(dt)
VAR mo = MONTH(dt)
VAR date2 = DATE(yr,mo,1)
RETURN (date2-1)+0.99999

or 

Column = 
VAR dt = DATE(2023,8,15)
VAR yr = YEAR(dt)
VAR mo = MONTH(dt)
VAR date2 = DATE(yr,mo,1)
RETURN (date2-1)+CONVERT(TIME(23,59,59),DOUBLE)

 

 

 

smpa01_0-1675790584176.png

replace GETTODAY() with TODAY() in DAX

Why 0.99999 works here I have no idea,

@AlexisOlson  do you know why it works? Can we achieve that part through a calculation rather than hardcoding

 

Did I answer your question? Mark my post as a solution!
Proud to be a Super User!
My custom visualization projects
Plotting Live Sound: Viz1
Beautiful News:Viz1, Viz2, Viz3
Visual Capitalist: Working Hrs

@smpa01 You're subtracting a day and then adding back almost a whole day.

 

(1-0.99999) days = 0.000001 days = 0.864 seconds.

 

So, essentially, you're taking midnight on the first of the month and subtracting roughly one second.

 

Since this is in the Power Query forum, I'd recommend

Date.StartOfMonth(DateTime.LocalNow()) - #duration(0,0,0,1)

 

In DAX, I'd recommend

EOMONTH ( TODAY(), -1 ) + TIME ( 23, 59, 59 )

 

Thank you I'll have a play with this.

Daryl-Lynch-Bzy
Resident Rockstar
Resident Rockstar

Hi @SuzieKidd - Could you please explain what you are trying to achieve with this formula? 

Please note that the DAX DATEADD function does not support seconds, minutes and hours like its SQL cousin.  You may consider using the add duration functionality in Power Query, or add a DAX functions that convert datetime to seconds (a bit like UNIX Timestamp).

Thank you

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