Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
5 years ago
Solved

Indexing with a custom increment

Hello, I'm trying to find an M formula that with increase the increment by 1 after every 3 rows.  For example:

 

Row #     Index

1             1

2             1

3             1

4             2

5             2

6             2

7             3

8             3

9             3

 

Thanks very much for any suggestions!

Need Help
  • v-jingzhang's avatar
    v-jingzhang
    4 years ago

    Hi Anonymous 

     

    You can achieve this by the GUI without any custom formula. Follow below steps!

     

    First add an Index column starting from 1.

     

    Then divide Index column by 3. From Transform tab > (Number Column) Standard > Divide.

     

    Finally round up Index column. Transform > (Number Column) Rounding > Round Up.

     

    Anyway, if you want a single M formula to get the same result, you can combine above three steps into one step. Paste below code into the formula bar and modify previous step name.

    = Table.TransformColumns(Table.AddIndexColumn(#"Changed Type", "Index", 1, 1, Int64.Type), {{"Index", each Number.RoundUp(_ / 3), type number}})

     

    Regards,
    Community Support Team _ Jing
    If this post helps, please Accept it as the solution to help other members find it.

  • Anonymous's avatar
    Anonymous
    4 years ago

    Thanks very much - this is a great solution!

4 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable
    5 years ago

    This would work. If your prior step is named LastStep, add a new step. In the formula bar, type:

     

    = Table.AddColumn(LastStep, "NewIndex", each if Number.Mod([Index], 3) = 0 then [Index]/3 else null)

     

    Then you can use Fill Up function in the GUI for the missing values.

     

    --Nate

     

    • Anonymous's avatar
      Anonymous
      Not applicable
      4 years ago

      Thank you very much!

  • v-jingzhang's avatar
    v-jingzhang
    Community Support
    4 years ago

    Hi Anonymous 

     

    You can achieve this by the GUI without any custom formula. Follow below steps!

     

    First add an Index column starting from 1.

     

    Then divide Index column by 3. From Transform tab > (Number Column) Standard > Divide.

     

    Finally round up Index column. Transform > (Number Column) Rounding > Round Up.

     

    Anyway, if you want a single M formula to get the same result, you can combine above three steps into one step. Paste below code into the formula bar and modify previous step name.

    = Table.TransformColumns(Table.AddIndexColumn(#"Changed Type", "Index", 1, 1, Int64.Type), {{"Index", each Number.RoundUp(_ / 3), type number}})

     

    Regards,
    Community Support Team _ Jing
    If this post helps, please Accept it as the solution to help other members find it.

    • Anonymous's avatar
      Anonymous
      Not applicable
      4 years ago

      Thanks very much - this is a great solution!