Forum Discussion
Expression.Error: There is an unknown identifier. Did you use the [field] shorthand for a _[field] o
Hi all, I'm trying to filter one table by the results of another table in Power Query but I am getting the very useful error of
"Expression.Error: There is an unknown identifier. Did you use the [field] shorthand for a _[field] outside of an 'each' expression?"
Can anyone let me know what I'm doing wrong here please?
"let
Source = Sql.Database("sql1.database.windows.net", "db1", [CommandTimeout=#duration(0, 5, 0, 0)]),
InventoryDimension = Source{[Schema="RPT",Item="InventoryDimension"]}[Data],
Custom1 = let
l = Table.SelectRows("Sales",each [Inventory Dimension Key]),
res = Table.SelectRows([Inventory Dimension Key],each List.Contains(l,[Inventory Dimension Key]))
in
res
in
Custom1"
Hi Toast36
Thank you for reaching out to the Microsoft Community Forum.
A special thanks to dufoq3 for responding on this topic.It looks like the issue arises from a cyclic reference when filtering the InventoryDimension table using the Sales table.
Try buffering the Sales table before using it for filtering:let
Source = Sql.Database("sql1.database.windows.net", "db1", [CommandTimeout=#duration(0, 5, 0, 0)]),
Sales = Table.Buffer(Source{[Schema="RPT", Item="Sales"]}[Data]),
InventoryDimension = Source{[Schema="RPT", Item="InventoryDimension"]}[Data],
SalesKeys = List.Distinct(Sales[Inventory Dimension Key]),
FilteredInventory = Table.SelectRows(InventoryDimension, each List.Contains(SalesKeys, [Inventory Dimension Key]))
in
FilteredInventory
If my response has resolved your query, please mark it as the Accepted Solution to assist others. Additionally, a 'Kudos' would be appreciated if you found my response helpful.
Thank You
8 Replies
- dufoq3
Community Champion
Hi Toast36,
check this:
let Source = Sql.Database("sql1.database.windows.net", "db1", [CommandTimeout=#duration(0, 5, 0, 0)]), InventoryDimension = Source{[Schema="RPT",Item="InventoryDimension"]}[Data], Custom1 = let l = TableName[ColumnName], //i.e. Sales[Inventory Dimension Key] column which you want to filter by res = Table.SelectRows(TableName,each List.Contains(l, [Inventory Dimension Key])) //TableName you want to filter in res in Custom1 - v-karpurapud
Community Support
Hi Toast36
Thank you for reaching out to the Microsoft Community Forum.
A special thanks to dufoq3 for responding on this topic.It looks like the issue arises from a cyclic reference when filtering the InventoryDimension table using the Sales table.
Try buffering the Sales table before using it for filtering:let
Source = Sql.Database("sql1.database.windows.net", "db1", [CommandTimeout=#duration(0, 5, 0, 0)]),
Sales = Table.Buffer(Source{[Schema="RPT", Item="Sales"]}[Data]),
InventoryDimension = Source{[Schema="RPT", Item="InventoryDimension"]}[Data],
SalesKeys = List.Distinct(Sales[Inventory Dimension Key]),
FilteredInventory = Table.SelectRows(InventoryDimension, each List.Contains(SalesKeys, [Inventory Dimension Key]))
in
FilteredInventory
If my response has resolved your query, please mark it as the Accepted Solution to assist others. Additionally, a 'Kudos' would be appreciated if you found my response helpful.
Thank You - v-karpurapud
Community Support
Hi Toast36
May I ask if you have resolved this issue? If so, please mark the helpful reply and accept it as the solution. This will be helpful for other community members who have similar problems to solve it faster.
Thank you.
- v-karpurapud
Community Support
Hi Toast36
I wanted to check if you had the opportunity to review the information provided. Please feel free to contact us if you have any further questions. If my response has addressed your query, please accept it as a solution and give a 'Kudos' so other members can easily find it.
Thank you. - v-karpurapud
Community Support
Hi Toast36
I hope this information is helpful. Please let me know if you have any further questions or if you'd like to discuss this further. If this answers your question, please Accept it as a solution and give it a 'Kudos' so others can find it easily.
Thank you.