This time we’re going bigger than ever. Fabric, Power BI, SQL, AI and more. We're covering it all. You won't want to miss it.
Learn moreDid you hear? There's a new SQL AI Developer certification (DP-800). Start preparing now and be one of the first to get certified. Register now
I have a table like this:
| Name | Date | Type |
| A | 7-Jan-25 10-Jan-25 25-Jan-25 25-Jan-25 | bus |
| B | car | |
| C | ship | |
| D | car |
And expected output is:,how to do this in power query
| Name | Date | Type |
| A | 07-Jan-25 | bus |
| B | 10-Jan-25 | car |
| C | 25-Jan-25 | ship |
| D | 25-Jan-25 | car |
Solved! Go to Solution.
Hi @Antmkjr, check this:
Output
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
ColumnsToList = Table.TransformColumns(Source, {}, each List.Select(Text.Split(_, "#(lf)"), (x)=> not List.Contains({"null", ""}, x)) ),
ColNames = Table.ColumnNames(ColumnsToList),
Records = List.Buffer(Table.ToRecords(ColumnsToList)),
Lg = List.Generate(
()=> [ x = 0, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}?) ],
each [x] < List.Count(Records),
each [ x = [x]+1, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}? ?? Record.FieldOrDefault(Records{0}, w){x}? ) ],
each [rec]
),
ToTable = Table.FromRows(Lg, ColNames)
in
ToTable
pls try this
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
Replace = Table.ReplaceValue(Source, (x)=>x,(x)=>x, (x,y,z)=>Text.Split(Source[Date]{0}, "#(lf)") ,{"Date"}),
Index = Table.AddIndexColumn(Replace, "Index", 0, 1, Int64.Type),
AddColumn = Table.AddColumn(Index, "tmp", each [Date]{[Index]}),
RemoveCol= Table.RemoveColumns(AddColumn,{"Date", "Index"})
in
RemoveCol
Please check this one
let
Source = Excel.CurrentWorkbook(){[Name="Table2"]}[Content],
Custom1 = Table.FromColumns({ Source[Name ],Text.Split(Source[Date]{0},"#(lf)"),Source[Type]})
in
Custom1
To solve this problem, select column Date and go to home tab and then pick split column command (by delimiter) with the below setting
to reach your solution
pls try this
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
Replace = Table.ReplaceValue(Source, (x)=>x,(x)=>x, (x,y,z)=>Text.Split(Source[Date]{0}, "#(lf)") ,{"Date"}),
Index = Table.AddIndexColumn(Replace, "Index", 0, 1, Int64.Type),
AddColumn = Table.AddColumn(Index, "tmp", each [Date]{[Index]}),
RemoveCol= Table.RemoveColumns(AddColumn,{"Date", "Index"})
in
RemoveCol
Hi @Antmkjr, check this:
Output
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
ColumnsToList = Table.TransformColumns(Source, {}, each List.Select(Text.Split(_, "#(lf)"), (x)=> not List.Contains({"null", ""}, x)) ),
ColNames = Table.ColumnNames(ColumnsToList),
Records = List.Buffer(Table.ToRecords(ColumnsToList)),
Lg = List.Generate(
()=> [ x = 0, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}?) ],
each [x] < List.Count(Records),
each [ x = [x]+1, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}? ?? Record.FieldOrDefault(Records{0}, w){x}? ) ],
each [rec]
),
ToTable = Table.FromRows(Lg, ColNames)
in
ToTable
Check out the April 2026 Power BI update to learn about new features.
Sign up to receive a private message when registration opens and key events begin.
If you have recently started exploring Fabric, we'd love to hear how it's going. Your feedback can help with product improvements.