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I have a table like this:
Name | Date | Type |
A | 7-Jan-25 10-Jan-25 25-Jan-25 25-Jan-25 | bus |
B | car | |
C | ship | |
D | car |
And expected output is:,how to do this in power query
Name | Date | Type |
A | 07-Jan-25 | bus |
B | 10-Jan-25 | car |
C | 25-Jan-25 | ship |
D | 25-Jan-25 | car |
Solved! Go to Solution.
Hi @Antmkjr, check this:
Output
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
ColumnsToList = Table.TransformColumns(Source, {}, each List.Select(Text.Split(_, "#(lf)"), (x)=> not List.Contains({"null", ""}, x)) ),
ColNames = Table.ColumnNames(ColumnsToList),
Records = List.Buffer(Table.ToRecords(ColumnsToList)),
Lg = List.Generate(
()=> [ x = 0, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}?) ],
each [x] < List.Count(Records),
each [ x = [x]+1, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}? ?? Record.FieldOrDefault(Records{0}, w){x}? ) ],
each [rec]
),
ToTable = Table.FromRows(Lg, ColNames)
in
ToTable
pls try this
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
Replace = Table.ReplaceValue(Source, (x)=>x,(x)=>x, (x,y,z)=>Text.Split(Source[Date]{0}, "#(lf)") ,{"Date"}),
Index = Table.AddIndexColumn(Replace, "Index", 0, 1, Int64.Type),
AddColumn = Table.AddColumn(Index, "tmp", each [Date]{[Index]}),
RemoveCol= Table.RemoveColumns(AddColumn,{"Date", "Index"})
in
RemoveCol
Please check this one
let
Source = Excel.CurrentWorkbook(){[Name="Table2"]}[Content],
Custom1 = Table.FromColumns({ Source[Name ],Text.Split(Source[Date]{0},"#(lf)"),Source[Type]})
in
Custom1
To solve this problem, select column Date and go to home tab and then pick split column command (by delimiter) with the below setting
to reach your solution
pls try this
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
Replace = Table.ReplaceValue(Source, (x)=>x,(x)=>x, (x,y,z)=>Text.Split(Source[Date]{0}, "#(lf)") ,{"Date"}),
Index = Table.AddIndexColumn(Replace, "Index", 0, 1, Int64.Type),
AddColumn = Table.AddColumn(Index, "tmp", each [Date]{[Index]}),
RemoveCol= Table.RemoveColumns(AddColumn,{"Date", "Index"})
in
RemoveCol
Hi @Antmkjr, check this:
Output
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WclTSUTLX9UrM0zUyjckzNIAzjUwxmUC1SaXFSrE60UpOQDYQJScWgbnOEG5xRmYBmO+CJB0LAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Name = _t, Date = _t, Type = _t]),
ColumnsToList = Table.TransformColumns(Source, {}, each List.Select(Text.Split(_, "#(lf)"), (x)=> not List.Contains({"null", ""}, x)) ),
ColNames = Table.ColumnNames(ColumnsToList),
Records = List.Buffer(Table.ToRecords(ColumnsToList)),
Lg = List.Generate(
()=> [ x = 0, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}?) ],
each [x] < List.Count(Records),
each [ x = [x]+1, rec = List.Transform(ColNames, (w)=> Record.FieldOrDefault(Records{x}, w){0}? ?? Record.FieldOrDefault(Records{0}, w){x}? ) ],
each [rec]
),
ToTable = Table.FromRows(Lg, ColNames)
in
ToTable
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