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I'm trying to create a calculated column like
Solved! Go to Solution.
Hi @selected_ ,
For the rankx function, the basis for processing the same ranking, skip stands for sparse ranking, and the next ranking is equal to the number of all previous rankings + 1; dense stands for dense ranking, which only accumulates the ranking, regardless of the number.
Therefore, only the following two results can be obtained for the rank function. If you want to get a continuous and uninterrupted ranking. You can create a column index after sorting to get the desired result.
C1 = RANKX('Table (2)',[Value],,ASC,Dense)
C2 = RANKX('Table (2)',[Value],,ASC,Skip)
You can use the Performance Analyzer to view the operating status of the created calculated column and measure to optimize.
related document link: Use Performance Analyzer to examine report element performance in Power BI Desktop - Power BI | Micr...
Best Regards,
Henry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @selected_ ,
For the rankx function, the basis for processing the same ranking, skip stands for sparse ranking, and the next ranking is equal to the number of all previous rankings + 1; dense stands for dense ranking, which only accumulates the ranking, regardless of the number.
Therefore, only the following two results can be obtained for the rank function. If you want to get a continuous and uninterrupted ranking. You can create a column index after sorting to get the desired result.
C1 = RANKX('Table (2)',[Value],,ASC,Dense)
C2 = RANKX('Table (2)',[Value],,ASC,Skip)
You can use the Performance Analyzer to view the operating status of the created calculated column and measure to optimize.
related document link: Use Performance Analyzer to examine report element performance in Power BI Desktop - Power BI | Micr...
Best Regards,
Henry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi @selected_ .
You can use the following DAX to create a calculated Index Column,
Index=
RANKX(
FILTER(table,
EARLIER(table[random_column])>table[random_column]),
table[value column],,ASC)
Regards,
Sanket Bhagwat.
If this posts helps , then please mark it as 'Accept As Solution' and give it a big thumbs up.
Same issue, I get same value back as 1,1,1,1,1,2,2,2,3,3,4
I need unique index column for all rows.
There is a workaround but it would be helpful only if you are sourcing your data from 'Import' mode.
If so, then I would suggest you to first add a custom Index Column using Query Editor and then use a DAX function like,
Index1=RANKX(
Filter(
table,
EARLIER(table[random_column)>table(random_column),
[Index],,ASC).
Although most of the users would not like this way of doing it as then we would have 2 Index columns(redudant column) and also it is not a suitable approach, but it definitely serves the purpose.
Try and let me know.
Regards,
Sanket Bhagwat.
If this posts helps, then do mark it as 'Accept as Solution' and give it a big thumbs up so that others users could find it quickly.
Can you please share your sample data?
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