Forum Discussion
create index with measure
I'm trying to create a calculated column like
Hi selected_ ,
For the rankx function, the basis for processing the same ranking, skip stands for sparse ranking, and the next ranking is equal to the number of all previous rankings + 1; dense stands for dense ranking, which only accumulates the ranking, regardless of the number.
Therefore, only the following two results can be obtained for the rank function. If you want to get a continuous and uninterrupted ranking. You can create a column index after sorting to get the desired result.C1 = RANKX('Table (2)',[Value],,ASC,Dense)C2 = RANKX('Table (2)',[Value],,ASC,Skip)You can use the Performance Analyzer to view the operating status of the created calculated column and measure to optimize.
related document link: Use Performance Analyzer to examine report element performance in Power BI Desktop - Power BI | Microsoft Docs
Best Regards,
Henry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
5 Replies
- v-henryk-mstf
Community Support
Hi selected_ ,
For the rankx function, the basis for processing the same ranking, skip stands for sparse ranking, and the next ranking is equal to the number of all previous rankings + 1; dense stands for dense ranking, which only accumulates the ranking, regardless of the number.
Therefore, only the following two results can be obtained for the rank function. If you want to get a continuous and uninterrupted ranking. You can create a column index after sorting to get the desired result.C1 = RANKX('Table (2)',[Value],,ASC,Dense)C2 = RANKX('Table (2)',[Value],,ASC,Skip)You can use the Performance Analyzer to view the operating status of the created calculated column and measure to optimize.
related document link: Use Performance Analyzer to examine report element performance in Power BI Desktop - Power BI | Microsoft Docs
Best Regards,
Henry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly. - AnonymousNot applicable
Hi @selected_ .
You can use the following DAX to create a calculated Index Column,
Index=
RANKX(
FILTER(table,
EARLIER(table[random_column])>table[random_column]),
table[value column],,ASC)Regards,
Sanket Bhagwat.
If this posts helps , then please mark it as 'Accept As Solution' and give it a big thumbs up.
- selected_
Helper IV
Same issue, I get same value back as 1,1,1,1,1,2,2,2,3,3,4
I need unique index column for all rows.
- AnonymousNot applicable
Can you please share your sample data?