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blazko's avatar
blazko
Helper III
7 years ago
Solved

common character position

Hi! I need help with finding the the common character (or characters) in column (by a category from another colummn). ex '123G456', '789G321' have common G on third position. So im looking a column ...
  • Zubair_Muhammad's avatar
    Zubair_Muhammad
    7 years ago

    blazko 

     

    Try this.

    Please see attached file's Query Editor as well for steps

     

     

    let
        Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("dcpBCoNADIXhu8xaQhJnxmSttIuK4FLEhbjoBXoAT+PBPEknhYKKs3vv5xtHt8wfcoUL9VPRx8fw+p993QDcVJyJxKYLt4RTRSZEmkXTBrCdyBGo/ABxDoRo8a1yB8oUhepeGLE1YBsA2iNQi8RlFpBFlSoLKosx+AuYvg==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t, Column3 = _t]),
        #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", type text}, {"Column2", type text}, {"Column3", type text}}),
        #"Grouped Rows" = Table.Group(#"Changed Type", {"Column1"}, {{"ALL", each _[Column2], type list}}),
        #"Added Custom2" = Table.AddColumn(#"Grouped Rows", "Custom.2", each Text.Combine(Table.AddColumn(Table.FromColumns(List.Transform([ALL],each Text.ToList(_))),"Result",each 
    let mylist=List.Distinct(Record.ToList(_)),
    mycount=List.Count(mylist)
    in
    if mycount=1 then Text.Combine(mylist) else "."
    )[Result])),
        #"Expanded ALL" = Table.ExpandListColumn(#"Added Custom2", "ALL")
    in
        #"Expanded ALL"