Grouping test count

[brettg]

Hello,

I currently have a table populated with values, 1,2,3.. etc.

I am counting repeat test users with the following;

Count = 
CALCULATE(COUNTROWS('Table'),FILTER(ALLSELECTED('Table'),[UserID]=MAX('Table'[UserID]) &&  [TestDateTime]>=MIN('Table'[TestDateTime]) && [TestDateTime]<=MAX('Table'[TestDateTime])))

I am then grouping them into number of tests with;

Count(again based on meassure) = 
var _t=SUMMARIZE('Table','Table'[UserID],"Count by UserID",[Count])
return COUNTROWS(FILTER(_t,[Count by UserID]=MAX('New Table'[Test])))+0

Can anyone think of a way to do this where I can group into 1 test, 2 tests, 3-5 tests etc.. ?

Many thanks

[v-yalanwu-msft · Accepted solution]

Hi, @brettg;

Try to enter a table.

Create a column 

Test2 = [start]&"-"&[end]

then create a measure.

Count(again based on meassure2) = 
var _t=SUMMARIZE('Table','Table'[UserID],"Count by UserID",[Count])
return COUNTROWS(FILTER(_t,[Count by UserID]<=MAX('Table (2)'[end])&&[Count by UserID]>=MAX('Table (2)'[start])))+0

 The final output is shown below:

Best Regards,
Community Support Team _ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[brettg]

Hi @v-yalanwu-msft 

This is perfect - thank you! 🙂

[brettg]

Hi @v-yalanwu-msft 

Thank you for taking a look! I have attached a link to access my sample file. 

https://drive.google.com/drive/folders/1paF2gfnMvLDQJ5r-re0y0zMmuqLQlKvL?usp=sharing

Basically, instead of my value table being 1,2,3,4,5.. etc. I would like to group the number of tests; 1 test, 2-5 tests 6-10 tests etc

Many thanks,

Brett

[v-yalanwu-msft]

Hi, @brettg ;

Could you please consdier sharing more details about it and posting expected result so it is clear on what needs to be implemented? And It would be great if there is a sample file without any sesentive information here.
It makes it easier to give you a solution.

Best Regards,
Community Support Team _ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.