Forum Discussion
Counting working days
I have 2 tables, a Member table and a Date table. Some members have non-working days. I want to calculate the number of non working days for any filtered date range for each member. I have a Weekday column in the Date table that numbers each Day value 1-7, and a Non Working Days value in the Member table that identifies the Weekday value of a each members non work day. Members without non work days have null vallue. That value is a Conditional Column. What is the DAX to accomplish this in a measure?
Date Table:
| Date | Weekday | Weekday Name |
| 1/1/2022 | 7 | Saturday |
| 1/2/2022 | 1 | Sunday |
| 1/3/2022 | 2 | Monday |
Member Table:
| Name | Non Working Day |
| John Smith | null |
| Jessica Rabbit | 2 |
| Homer Simpson | 6 |
Hi, msimmonsmcse
Try to create a measure like this:Measure = var _TotalDays= CALCULATE( COUNT('DataTable'[WeekDay]), REMOVEFILTERS('Member Table'[Name]) ) var _non_workingDays= CALCULATE( COUNT('DataTable'[WeekDay]), FILTER('DataTable','DataTable'[WeekDay] in VALUES('Member Table'[Non Working Day]))) var _result=_TotalDays-_non_workingDays return _resultResult:
Please refer to the attachment below for details.
Hope this helps.
Best Regards,
Community Support Team _ Zeon ZhengIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- AlexisOlsonSuper User
I think you can write the base logic along these lines:
Non-Working Day Count = VAR NonWorkDay = SELECTEDVALUE ( Member[Non Working Day] ) RETURN COUNTROWS ( FILTER ( DateTable, DateTable[Weekday] <> NonWorkDay ) ) - v-angzheng-msftCommunity Support
Hi, msimmonsmcse
Try to create a measure like this:Measure = var _TotalDays= CALCULATE( COUNT('DataTable'[WeekDay]), REMOVEFILTERS('Member Table'[Name]) ) var _non_workingDays= CALCULATE( COUNT('DataTable'[WeekDay]), FILTER('DataTable','DataTable'[WeekDay] in VALUES('Member Table'[Non Working Day]))) var _result=_TotalDays-_non_workingDays return _resultResult:
Please refer to the attachment below for details.
Hope this helps.
Best Regards,
Community Support Team _ Zeon ZhengIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.