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elemesey's avatar
elemesey
Frequent Visitor
2 years ago
Solved

Count Value Lookup

Good day everyone,

I'm a beginner to DAX and need assistance. I have a list of customers that have made sales, and I'd like to know the total number of customers who have not made sales during the specified time frame. 



I'm also open to suggestions for the proper name for this subject 😅 When you view this post, I appreciate all of your help 😊

Thank you.

Test File - https://drive.google.com/file/d/1kbQsdWT47QYGqnHOemsU040vrYcETNM1/view?usp=drive_link 

Need Help
  • Anonymous's avatar
    Anonymous
    2 years ago

    Hi elemesey ,

     

    I suggest you to try code as below.

    Count of Customer no sales =
VAR _COUNTBYREGION =
    SUMMARIZE (
        Sales,
        Sales[Region],
        "COUNTBYREGION",
            CALCULATE (
                DISTINCTCOUNT ( Allcustomer[Customer] ),
                ALLEXCEPT ( Allcustomer, Sales[Region] )
            )
    )
RETURN
    SUMX ( _COUNTBYREGION, [COUNTBYREGION] )
        - CALCULATE ( DISTINCTCOUNT ( Allcustomer[Customer] ) )

    Result is as below.

     

    Best Regards,

    Rico Zhou

     

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

3 Replies

    • Anonymous's avatar
      Anonymous
      Not applicable
      2 years ago

      Hi elemesey ,

       

      I suggest you to try code as below.

      Count of Customer no sales =
VAR _COUNTBYREGION =
    SUMMARIZE (
        Sales,
        Sales[Region],
        "COUNTBYREGION",
            CALCULATE (
                DISTINCTCOUNT ( Allcustomer[Customer] ),
                ALLEXCEPT ( Allcustomer, Sales[Region] )
            )
    )
RETURN
    SUMX ( _COUNTBYREGION, [COUNTBYREGION] )
        - CALCULATE ( DISTINCTCOUNT ( Allcustomer[Customer] ) )

      Result is as below.

       

      Best Regards,

      Rico Zhou

       

      If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

      • elemesey's avatar
        elemesey
        Frequent Visitor
        2 years ago

        Hi Anonymous,

        It works fantastic, thank you very much! 😊