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tomekm
Helper III
Helper III

Calculate if a column contains some text for each occurrence of a unique value

Hello,

 

I'm trying to come up with a formula for the following scenario. Any help would be greatly appreciated.

 

For a given Primary Key in column D ("R_PK1"), IF the Primary Key is present EXACTLY 2 times in the table, AND if column B equals "BBB" in any of the 2 rows for that Primary Key, then give me "some text" else "some other text".

 

Below is the sample data. Thank you for your help!

 

Code:Category:Type:R_PK1:Output column:
abcAAAShared1111111some text
xyzBBBShared1111111some text
cdbAAAShared2222222some other text
wsdBBBShared2222222some other text
gjkFFFShared2222222some other text

 

2 ACCEPTED SOLUTIONS
Ashish_Mathur
Super User
Super User

Hi,

This calculated column formula works

Column = if(and(CALCULATE(COUNTROWS(Data),FILTER(Data,Data[R_PK1]=EARLIER(Data[R_PK1])))=2,CALCULATE(COUNTROWS(Data),FILTER(Data,Data[R_PK1]=EARLIER(Data[R_PK1])&&Data[Category]="BBB"))>=1),"Some Text","Some other text")

Hope this helps.

Untitled.png


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/

View solution in original post

v-yangliu-msft
Community Support
Community Support

Hi  @tomekm ,

Here are the steps you can follow:

1. Create calculated column.

Output column =
var _count=COUNTX(FILTER(ALL('Table'),'Table'[R_PK1:]=EARLIER('Table'[R_PK1:])),[R_PK1:])
var _category=SELECTCOLUMNS(FILTER(ALL('Table'),[R_PK1:]=EARLIER('Table'[R_PK1:])),"1",'Table'[Category:])
return
IF(
    _count=2&&"BBB" in _category,"Some Text","Some other text")

2. Result:

vyangliumsft_0-1645769948176.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

7 REPLIES 7
v-yangliu-msft
Community Support
Community Support

Hi  @tomekm ,

Here are the steps you can follow:

1. Create calculated column.

Output column =
var _count=COUNTX(FILTER(ALL('Table'),'Table'[R_PK1:]=EARLIER('Table'[R_PK1:])),[R_PK1:])
var _category=SELECTCOLUMNS(FILTER(ALL('Table'),[R_PK1:]=EARLIER('Table'[R_PK1:])),"1",'Table'[Category:])
return
IF(
    _count=2&&"BBB" in _category,"Some Text","Some other text")

2. Result:

vyangliumsft_0-1645769948176.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

Ashish_Mathur
Super User
Super User

Hi,

This calculated column formula works

Column = if(and(CALCULATE(COUNTROWS(Data),FILTER(Data,Data[R_PK1]=EARLIER(Data[R_PK1])))=2,CALCULATE(COUNTROWS(Data),FILTER(Data,Data[R_PK1]=EARLIER(Data[R_PK1])&&Data[Category]="BBB"))>=1),"Some Text","Some other text")

Hope this helps.

Untitled.png


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/

Thank you!

You are welcome.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
PijushRoy
Super User
Super User

Hi @tomekm 

Please try this, (change table name and col name as per quirement)
= VAR _count2 = DISTINCTCOUNT('Table'[R_PK1])
RESULT
SWITCH(
TRUE(),
_count2 = 2 && 'Table'[Category] = "BBB", "Some Test",
"Some Other Test")


If not solved, please keep posted (paste from excel, your data is broken when I try to use)


If solve your requirement, please mark this answer as SOLUTION
If this comment helps you, please LIKE this comment/Kudos

Code:Category:Type:R_PK1:Output column:
abcAAAShared1111111some text
xyzBBBShared1111111some text
cdbAAAShared2222222some other text
wsdCCCShared2222222some other text
gjkFFFShared2222222some other text

Thank you for the quick response. Unfortunately this formula didn't work for me. I'm pasting the data in tabular format here:

 

Code:Category:Type:R_PK1:Output column:
abcAAAShared1111111some text
xyzBBBShared1111111some text
cdbAAAShared2222222some other text
wsdCCCShared2222222some other text
gjkFFFShared2222222some other text

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