Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

To celebrate FabCon Vienna, we are offering 50% off select exams. Ends October 3rd. Request your discount now.

Reply
Anonymous
Not applicable

Help splitting this column

Sample.jpg

 

I need to split this by dd/mm/yyyy (UK date format).

I'm in need of an DAX formula that'll extract the date portion (02022024) of the Source Name column and then return the result in the above manner. 

If someone can guide me in this, it'll be wonderful. I'm very raw with DAX. 

1 ACCEPTED SOLUTION
govindarajan_d
Super User
Super User

Hi @Anonymous,

 

Can you please try this:

 

 

Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

 

 

 

govindarajan_d_0-1707393035791.png

 

Upvote and accept as a solution if it helps!

 

View solution in original post

4 REPLIES 4
govindarajan_d
Super User
Super User

Hi @Anonymous,

 

Can you please try this:

 

 

Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

 

 

 

govindarajan_d_0-1707393035791.png

 

Upvote and accept as a solution if it helps!

 

Hi @Anonymous ,

 

Did the solution work?

Anonymous
Not applicable

You're a star! Thanks. 

Anonymous
Not applicable

Hi, sorry for the very late response. I'm going to check now and get back to you. 

Helpful resources

Announcements
September Power BI Update Carousel

Power BI Monthly Update - September 2025

Check out the September 2025 Power BI update to learn about new features.