Help splitting this column

[Anonymous]

I need to split this by dd/mm/yyyy (UK date format).

I'm in need of an DAX formula that'll extract the date portion (02022024) of the Source Name column and then return the result in the above manner. 

If someone can guide me in this, it'll be wonderful. I'm very raw with DAX. 

[govindarajan_d · Accepted solution]

Hi @Anonymous,

Can you please try this:

Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

Upvote and accept as a solution if it helps!

[govindarajan_d]

Hi @Anonymous ,

Did the solution work?

[Anonymous]

You're a star! Thanks. 

[Anonymous]

Hi, sorry for the very late response. I'm going to check now and get back to you.