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Shak1254
Helper I
Helper I

Help splitting this column

Sample.jpg

 

I need to split this by dd/mm/yyyy (UK date format).

I'm in need of an DAX formula that'll extract the date portion (02022024) of the Source Name column and then return the result in the above manner. 

If someone can guide me in this, it'll be wonderful. I'm very raw with DAX. 

1 ACCEPTED SOLUTION
govindarajan_d
Super User
Super User

Hi @Shak1254,

 

Can you please try this:

 

 

Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

 

 

 

govindarajan_d_0-1707393035791.png

 

Upvote and accept as a solution if it helps!

 

View solution in original post

4 REPLIES 4
govindarajan_d
Super User
Super User

Hi @Shak1254,

 

Can you please try this:

 

 

Date =
VAR DatePosition =
    LEN ( Files[FileName] ) - LEN ( "ddmmyyyy" )
        - LEN ( ".xlsx" ) + 1
VAR DateString =
    MID ( Files[FileName], DatePosition, 8 )
RETURN
    FORMAT (
        DATE ( RIGHT ( DateString, 4 ), MID ( DateString, 3, 2 ), LEFT ( DateString, 2 ) ),
        "dd/mm/yyyy"
    )

 

 

 

govindarajan_d_0-1707393035791.png

 

Upvote and accept as a solution if it helps!

 

Hi @Shak1254 ,

 

Did the solution work?

You're a star! Thanks. 

Hi, sorry for the very late response. I'm going to check now and get back to you. 

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