Count repeated values on three columns

[superjam]

Hello:

I have a "Table" with three columns, A, B and C, filled with many different string values.

I want to find how many rows of that table have all three columns equal to another row in the table. In other words, find rows with duplicate "A+B+C". In a visual I would need a number, indicating how many non unique values there are, combining the three columns.

Is there a formula to achieve this or do I have to concatenate all three columns in one first and then somehow count the duplicates?

Thank you very much and regards.

[tamerj1]

Hi @superjam 
In general that depends on the filter context which essentially depens on the visual itself. However, The following should work in a card visual

Count =
COUNTROWS (
    DISTINCT ( SELECTCOLUMNS ( "A", 'Table'[A], "B", 'Table'[B], "C", 'Table'[C] ) )
)

[superjam]

Hello,

Just after posting the last response, I figured it out: create a new column concatenating the three columns and then use the idea of @FreemanZ to calculate the duplicate ones. 

[FreemanZ]

hi @superjam 

DISTINCT also accept table as argument.

[FreemanZ]

hi @superjam 

try like:

Measure =

COUNTROWS(TableName)-

COUNTROWS(DISTINCT(TableName))

[superjam]

Thank you, @FreemanZ 

The function DISTINCT() counts unique values in one column of the table. So, your measure gives the repeated values in one column.

But how about the following example:

Only one row is duplicated (marked in yellow), because only in that case all three columns are equal with each other. I hope this clarifies the problem.

Thanks again.