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Hello:
I have a "Table" with three columns, A, B and C, filled with many different string values.
I want to find how many rows of that table have all three columns equal to another row in the table. In other words, find rows with duplicate "A+B+C". In a visual I would need a number, indicating how many non unique values there are, combining the three columns.
Is there a formula to achieve this or do I have to concatenate all three columns in one first and then somehow count the duplicates?
Thank you very much and regards.
Hi @superjam
In general that depends on the filter context which essentially depens on the visual itself. However, The following should work in a card visual
Count =
COUNTROWS (
DISTINCT ( SELECTCOLUMNS ( "A", 'Table'[A], "B", 'Table'[B], "C", 'Table'[C] ) )
)
Hello,
Just after posting the last response, I figured it out: create a new column concatenating the three columns and then use the idea of @FreemanZ to calculate the duplicate ones.
Thank you, @FreemanZ
The function DISTINCT() counts unique values in one column of the table. So, your measure gives the repeated values in one column.
But how about the following example:
Only one row is duplicated (marked in yellow), because only in that case all three columns are equal with each other. I hope this clarifies the problem.
Thanks again.
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