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Rpxx
Regular Visitor

Average basket size containing SKU's

I have a table with ordered SKU's. One line is a one position on one order. In one order client can buy many different SKU's. I'd like to calculate and analize average basket size (value) included next SKU's. Could you help me?

 

For example for SKU 01111 it will be (order 001) SUM=6; (order 003)  SUM=16, so avg order is (16+6)/2=11

 

Date| No of order| SKU| Value
2022-12-01| 001| 02222| 2
2022-12-01| 001| 01111| 4
2022-12-01| 002| 02222| 10
2022-12-01| 003| 02222| 3
2022-12-01| 003| 04444| 2
2022-12-01| 003| 06666| 9
2022-12-01| 003| 01111| 2
2022-12-02| 004| 02222| 4
2022-12-02| 005| 03333| 2
2022-12-02| 005| 04444| 7
2022-12-02| 005| 01111| 4
2022-12-02| 006| 05555| 7

 

SKU| Avg basket size with SKU
011111| 11
022222| ?
1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi  @Rpxx ,

 

Here are the steps you can follow:

1. Create measure.

Avg basket size with SKU =
var _column=SELECTCOLUMNS(FILTER(ALL('Table'),'Table'[Date]=MAX('Table'[Date])&&'Table'[SKU]=MAX('Table'[SKU])),"1",[No of order])
var _count=
CALCULATE(DISTINCTCOUNT('Table'[No of order]),FILTER(ALL('Table'),
'Table'[SKU]=MAX('Table'[SKU])&&'Table'[Date]=MAX('Table'[Date])))
var _sum=
SUMX(FILTER(ALL('Table'),'Table'[No of order] in _column&&'Table'[Date]=MAX('Table'[Date])),[Value])
return
DIVIDE(_sum,_count)

2. Result:

vyangliumsft_0-1670549632093.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi  @Rpxx ,

 

Here are the steps you can follow:

1. Create measure.

Avg basket size with SKU =
var _column=SELECTCOLUMNS(FILTER(ALL('Table'),'Table'[Date]=MAX('Table'[Date])&&'Table'[SKU]=MAX('Table'[SKU])),"1",[No of order])
var _count=
CALCULATE(DISTINCTCOUNT('Table'[No of order]),FILTER(ALL('Table'),
'Table'[SKU]=MAX('Table'[SKU])&&'Table'[Date]=MAX('Table'[Date])))
var _sum=
SUMX(FILTER(ALL('Table'),'Table'[No of order] in _column&&'Table'[Date]=MAX('Table'[Date])),[Value])
return
DIVIDE(_sum,_count)

2. Result:

vyangliumsft_0-1670549632093.png

 

Best Regards,

Liu Yang

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly

This is my expected result. Could you help me? Date is not important...

Rpxx_1-1671449249955.png

 

 

Could you describe what is the next steps to calculate these numbers in your file? I don't understand...

Rpxx_0-1671443642486.png

 

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