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comish4lif2
Advocate II
Advocate II

Extract Text from Name of File being Imported

Is there an straightforward way in PQ or via a formula, new column, or measure to get the text from the name of the file being imported?

Or do I have to redo a few things and reimport this as a folder import??

1 ACCEPTED SOLUTION
Payeras_BI
Solution Sage
Solution Sage

Hi,

I understand your Source step equals to "Csv.Document(File.Contents(..."
Copy paste the function below and invoke it in your Source instead.

Payeras_BI_0-1686926713274.png

 

(Path as text) => 
let
FileName =  Text.BetweenDelimiters(Path, "_", ".txt", {0, RelativePosition.FromEnd}, 0),
Txt = Csv.Document(File.Contents(Path),[Delimiter=";", Encoding=1252, QuoteStyle=QuoteStyle.None]),
PromoteHeaders = Table.PromoteHeaders(Txt, [PromoteAllScalars=true]),
FileNameColumn = Table.AddColumn(PromoteHeaders, "FileName", each FileName)
in
FileNameColumn

 

Hope it helps.

 

If this post answered your question, please mark it as a solution to help other users find useful content.
Kudos are another nice way to acknowledge those who tried to help you.

J. Payeras
Mallorca, Spain

View solution in original post

3 REPLIES 3
Payeras_BI
Solution Sage
Solution Sage

Hi,

I understand your Source step equals to "Csv.Document(File.Contents(..."
Copy paste the function below and invoke it in your Source instead.

Payeras_BI_0-1686926713274.png

 

(Path as text) => 
let
FileName =  Text.BetweenDelimiters(Path, "_", ".txt", {0, RelativePosition.FromEnd}, 0),
Txt = Csv.Document(File.Contents(Path),[Delimiter=";", Encoding=1252, QuoteStyle=QuoteStyle.None]),
PromoteHeaders = Table.PromoteHeaders(Txt, [PromoteAllScalars=true]),
FileNameColumn = Table.AddColumn(PromoteHeaders, "FileName", each FileName)
in
FileNameColumn

 

Hope it helps.

 

If this post answered your question, please mark it as a solution to help other users find useful content.
Kudos are another nice way to acknowledge those who tried to help you.

J. Payeras
Mallorca, Spain
Payeras_BI
Solution Sage
Solution Sage

Hi @comish4lif2 ,

Assuming the file name is part of your Source step you could add a column extracting it using any of the functions you have available.

For instance: 

Text.BetweenDelimiters(Source,"\",".")

 

If this post answered your question, please mark it as a solution to help other users find useful content.
Kudos are another nice way to acknowledge those who tried to help you.

J. Payeras
Mallorca, Spain

Is the file name part of my source step? 

If I import a txt file, how do I get from "FIlename_06162023.txt" - to "06162023" in its own column.

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