cancel
Showing results for
Did you mean:
Helper III

Distinct Count based on multiple column

Hi,

I want to display value which is as described below.

My calculation is like this

var a =Distinct count of value 1

var b= Count of Value 2

var ans=b/a

I want to display ans as my result.

But Problem is there I have multiple records for all records. That means for value 1 (distinct) I got multiple values. So my calculation is not properly set as my requirement. So please help me in this case. If Found Unique count that is based on multiple column(value 1 and value 2) for var b.

Thanks.

1 ACCEPTED SOLUTION
Microsoft

Hi @Krunalbpatel,

Please change the formula of var b to the following formula:

```var b = COUNTROWS(
SUMMARIZE(Table,Table[Name],Table[Value1],Table[Value2])
)```

I create a table visual to display your expected result. For more details, you can review the example in this attached PBIX file:https://1drv.ms/u/s!AhsotbnGu1NogXByWhS2F551DemE.

Thanks,
Lydia Zhang

Community Support Team _ Lydia Zhang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
6 REPLIES 6
Community Champion

Hi Krunal,

Happy to help you with this. Please provide a snapshot of data and what are you trying to achieve.

Regards

Bhavesh

Thanks & Regards,
Bhavesh

Love the Self Service BI.
Helper III

Hi,

I have data like this

Id Name Value1 Value2

1 abc      1          1

2 abc      1          2

3 abc      1          3

4 pqr      2         1

5 pqr      2         2

6 abc      1          1

7 abc      1          2

8 mnq    3          1

9 pqr      2         1

10 xyz    4         2

Now my calculation is like this

var a = DISTINCTCOUNT(value1)

var b = COUNT(Value2)

My result wold give me like

abc 1 - 5

pqr  1 - 3

mnq 1 - 1

xyz   1 - 1

But I need

abc 1 - 3

pqr  1 - 2

mnq 1 - 1

xyz   1 - 1

For this I need to count distinct on multiple column so

1 abc      1          1

6 abc      1          1

this will result only 1

Thanks And Regards

Krunal Patel

Microsoft

Hi @Krunalbpatel,

Please change the formula of var b to the following formula:

```var b = COUNTROWS(
SUMMARIZE(Table,Table[Name],Table[Value1],Table[Value2])
)```

I create a table visual to display your expected result. For more details, you can review the example in this attached PBIX file:https://1drv.ms/u/s!AhsotbnGu1NogXByWhS2F551DemE.

Thanks,
Lydia Zhang

Community Support Team _ Lydia Zhang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Helper III

Hi Lydia Zhang,

Thank you for your reply. I got my solution and its works fine for me.

Thanks and Regards,

Krunal Patel

Resolver I

Hi Krunalbpatel,

Test= SUMX(DISTINCT('Table'[Value2]),CALCULATE( VALUES('Table' [Value2])))

I hope this helps,

Christian

Helper III

Hi cosborn1231,

No This will not help me. In this case I got the sum of distinct values but I want the distinct value count against value 1.

Thanks and Regards,

Krunal Patel