Get certified for free when you join Fabric Data Days 2026 and dive into Fabric, Power BI, SQL, AI, and other essential data skills.
Join nowJuly 7 - July 17 | Round 2 of the Power BI Dataviz World Championships. Don't miss your chance! Learn more
I have a column called Block Number in my table in which every imput ends with a letter. I want to create a new column which auto fills with yes or no depending on the letter?
This is what I thought it should look like but its coming up with a missing right parenthesis error?
=if(Text.End([Block Number],1)="T","YES",if(Text.End([Block Number],1)="V","YES",if(Text.End([Block Number],1)="W","YES", "NO")))
Any Help would be appreciated.
Solved! Go to Solution.
Hi @Elliot137 ,
You're using DAX IF syntax with M code functions.
In Power Query you could do something like this:
if List.Contains({"T", "V", "W"}, Text.End([Block Number], 1)) then "YES"
else "NO"
Pete
Proud to be a Datanaut!
No problem.
IF( thisThing, thenThatThing, elseOtherThing ) is DAX/Excel syntax.
if thisThing then thatThing else otherThing is M code/Power Query syntax.
Pete
Proud to be a Datanaut!
Hi @Elliot137 ,
You're using DAX IF syntax with M code functions.
In Power Query you could do something like this:
if List.Contains({"T", "V", "W"}, Text.End([Block Number], 1)) then "YES"
else "NO"
Pete
Proud to be a Datanaut!
Join us in Barcelona for FabCon and SQLCon, the Fabric, Power BI, SQL, and AI community event. Save €200 with code FABCMTY200.
Join Fabric Data Days 2026: 60 days of free live/on-demand sessions, challenges, study groups, and certification opportunities.