Forum Discussion
cdk319
2 years agoNew Member
Top N for each ID in Power Query
Hello,
I need to return 3 records for each person in a table. I really don't care if it's Top 3 or Last 3 or random. Each ID number (person) can have 1 to unlimited records (probably more like 15).
Basic setup is:
ResourceID | OrderID | Date | Other info/fields |
ABC-1 | 12301 | 1/1/24 |
|
ABC-1 | 12302 | 1/2/24 |
|
ABC-2 | 12303 | 1/3/24 |
|
ABC-3 | 12304 | 1/4/24 |
|
ABC-3 | 12305 | 1/5/24 |
|
ABC-3 | 12306 | 1/6/24 |
|
ABC-3 | 12307 | 1/7/24 |
|
So I want 3 OrderIDs for each ResourceID, or 2 or 1. I tried grouping.. I'm stuck. Help!
Table.Group and then take the first three rows using a custom aggregation
let Source = Table.FromColumns({ {"ABC-1","ABC-1","ABC-2","ABC-3","ABC-3","ABC-3","ABC-3"}, List.Numbers(12301,7), List.Dates(#date(2024,1,1),7,#duration(1,0,0,0))}, type table[ResourceID=text, OrderID=Int64.Type, Date=date]), #"Grouped Rows" = Table.Group(Source, {"ResourceID"}, { {"3 Rows", each Table.FirstN(_,3), type table [ResourceID=text, OrderID=number, Date=date]}}), #"Expanded 3 Rows" = Table.ExpandTableColumn(#"Grouped Rows", "3 Rows", {"OrderID", "Date"}) in #"Expanded 3 Rows"Results
1 Reply
- ronrsnfldSuper User
Table.Group and then take the first three rows using a custom aggregation
let Source = Table.FromColumns({ {"ABC-1","ABC-1","ABC-2","ABC-3","ABC-3","ABC-3","ABC-3"}, List.Numbers(12301,7), List.Dates(#date(2024,1,1),7,#duration(1,0,0,0))}, type table[ResourceID=text, OrderID=Int64.Type, Date=date]), #"Grouped Rows" = Table.Group(Source, {"ResourceID"}, { {"3 Rows", each Table.FirstN(_,3), type table [ResourceID=text, OrderID=number, Date=date]}}), #"Expanded 3 Rows" = Table.ExpandTableColumn(#"Grouped Rows", "3 Rows", {"OrderID", "Date"}) in #"Expanded 3 Rows"Results