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cdk319
New Member
2 years ago
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Top N for each ID in Power Query

Hello,

 

I need to return 3 records for each person in a table. I really don't care if it's Top 3 or Last 3 or random. Each ID number (person) can have 1 to unlimited records (probably more like 15).

 

Basic setup is:

ResourceID

OrderID

Date

Other info/fields

ABC-1

12301

1/1/24

 

ABC-1

12302

1/2/24

 

ABC-2

12303

1/3/24

 

ABC-3

12304

1/4/24

 

ABC-3

12305

1/5/24

 

ABC-3

12306

1/6/24

 

ABC-3

12307

1/7/24

 

 

So I want 3 OrderIDs for each ResourceID, or 2 or 1. I tried grouping.. I'm stuck. Help!

  • Table.Group and then take the first three rows using a custom aggregation

    let 
        Source = Table.FromColumns({
            {"ABC-1","ABC-1","ABC-2","ABC-3","ABC-3","ABC-3","ABC-3"},
            List.Numbers(12301,7),
            List.Dates(#date(2024,1,1),7,#duration(1,0,0,0))},
            type table[ResourceID=text, OrderID=Int64.Type, Date=date]),
        
        #"Grouped Rows" = Table.Group(Source, {"ResourceID"}, {
            {"3 Rows", each Table.FirstN(_,3), type table [ResourceID=text, OrderID=number, Date=date]}}),
        
        #"Expanded 3 Rows" = Table.ExpandTableColumn(#"Grouped Rows", "3 Rows", {"OrderID", "Date"})
    in 
        #"Expanded 3 Rows"

    Results

     

     

1 Reply

  • Table.Group and then take the first three rows using a custom aggregation

    let 
        Source = Table.FromColumns({
            {"ABC-1","ABC-1","ABC-2","ABC-3","ABC-3","ABC-3","ABC-3"},
            List.Numbers(12301,7),
            List.Dates(#date(2024,1,1),7,#duration(1,0,0,0))},
            type table[ResourceID=text, OrderID=Int64.Type, Date=date]),
        
        #"Grouped Rows" = Table.Group(Source, {"ResourceID"}, {
            {"3 Rows", each Table.FirstN(_,3), type table [ResourceID=text, OrderID=number, Date=date]}}),
        
        #"Expanded 3 Rows" = Table.ExpandTableColumn(#"Grouped Rows", "3 Rows", {"OrderID", "Date"})
    in 
        #"Expanded 3 Rows"

    Results