Forum Discussion
Anonymous
3 years agoNot applicable
Return a Split Column After Transformation
Hi folks, Is there an efficient way to return a previously split column (by row) back to a comma-separated list in a single cell after performing transformations on it? I have a table like the f...
- 3 years ago
Anonymous Do a Group By step like this:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjQ0VNJRCi1OLfJ0AbGCS1LLUpVidVBljEAyiTk5lWAZIyMjuIwxkOVVmpiHIWEKZLkWZSZjSJgBWSFFIB2xAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Job ID" = _t, #"Other Users" = _t, #"User Names" = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"Job ID", Int64.Type}, {"Other Users", type text}, {"User Names", type text}}), #"Grouped Rows" = Table.Group(#"Changed Type", {"Job ID"}, {{"User Names", each Text.Combine([User Names], ", "), type nullable text}}) in #"Grouped Rows"
Greg_Deckler
3 years agoCommunity Champion
Anonymous Do a Group By step like this:
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjQ0VNJRCi1OLfJ0AbGCS1LLUpVidVBljEAyiTk5lWAZIyMjuIwxkOVVmpiHIWEKZLkWZSZjSJgBWSFFIB2xAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [#"Job ID" = _t, #"Other Users" = _t, #"User Names" = _t]),
#"Changed Type" = Table.TransformColumnTypes(Source,{{"Job ID", Int64.Type}, {"Other Users", type text}, {"User Names", type text}}),
#"Grouped Rows" = Table.Group(#"Changed Type", {"Job ID"}, {{"User Names", each Text.Combine([User Names], ", "), type nullable text}})
in
#"Grouped Rows"