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jaryszek
Memorable Member
Memorable Member

Merge values from rows into one row

Hi Guys,

 

i have table like here:

1DeploymentsMap
6DeploymentsMap
3DeploymentsMap
6DeploymentsMap

 

and what i want to get is:

TableName|Index

DeploymentsMap1;3;6

 

how to do this?

I will have multiple TableNAmes in a column...

 

Please help,
Jacek

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi @jaryszek ,

 

Please try:

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUXJJLcjJr8xNzSsp9k0sUIrViVYywy5sjF3Y0NrI2tjaxNoUu7QRUNjRyRnMNoGxYwE=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", type text}, {"Column2", type text}}),
    #"Split Column by Delimiter" = Table.ExpandListColumn(Table.TransformColumns(#"Changed Type", {{"Column1", Splitter.SplitTextByDelimiter(";", QuoteStyle.Csv), let itemType = (type nullable text) meta [Serialized.Text = true] in type {itemType}}}), "Column1"),
    #"Removed Duplicates" = Table.Distinct(#"Split Column by Delimiter"),
    #"Grouped Rows" = Table.Group( #"Removed Duplicates", {"Column2"}, {{"Combined", each Text.Combine(List.Sort(List.Distinct([Column1])), ";")}})
in
    #"Grouped Rows"

Eyelyn9_0-1634783699207.png

 

Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

View solution in original post

4 REPLIES 4
Anonymous
Not applicable

Hi @jaryszek ,

 

Please try:

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUXJJLcjJr8xNzSsp9k0sUIrViVYywy5sjF3Y0NrI2tjaxNoUu7QRUNjRyRnMNoGxYwE=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", type text}, {"Column2", type text}}),
    #"Split Column by Delimiter" = Table.ExpandListColumn(Table.TransformColumns(#"Changed Type", {{"Column1", Splitter.SplitTextByDelimiter(";", QuoteStyle.Csv), let itemType = (type nullable text) meta [Serialized.Text = true] in type {itemType}}}), "Column1"),
    #"Removed Duplicates" = Table.Distinct(#"Split Column by Delimiter"),
    #"Grouped Rows" = Table.Group( #"Removed Duplicates", {"Column2"}, {{"Combined", each Text.Combine(List.Sort(List.Distinct([Column1])), ";")}})
in
    #"Grouped Rows"

Eyelyn9_0-1634783699207.png

 

Best Regards,
Eyelyn Qin
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

mahoneypat
Microsoft Employee
Microsoft Employee

You can do that by creating a Group By step on the Home tab, and then modifying the code in the Formula Bar to match this example.  To see how it works, just create a blank query, open the Advanced Editor and replace the text there with the M code below.

 

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUXJJLcjJr8xNzSsp9k0sUIrViVYywy5sTLzqWAA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Column1", type text}, {"Column2", type text}}),
    #"Grouped Rows" = Table.Group(#"Changed Type", {"Column2"}, {{"Combined", each Text.Combine(List.Sort(List.Distinct([Column1])), ";")}})
in
    #"Grouped Rows"

 

Pat





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Thank you it is working!

 

One more thing. 

Sometimes i will have already created strings as Value like "1;2;3;4;5":

 

1DeploymentsMap
6DeploymentsMap
3DeploymentsMap
1;2;3;4;5DeploymentsMap

 

And as result i would like to get 

1;2;3;4;5;6DeploymentsMap


so check if in list value exists, if not append. So check if there is alreadylist, if yes to not have duplicates --> 

appendto get only uniqes.

 

what i get using provided formula:

Column2Combined

DeploymentsMap1;1;2;3;4;5;3;6


Can you please advise also?

Best,
Jacek

jaryszek
Memorable Member
Memorable Member

And the problem which i can have also that sometimes 

Value can be an array like "1;2;3;4;5" and in this case i should keep whole array plus append missing rows.

So in this case i would append "6" to get "1;2;3;4;5;6"

 

Best,
Jacek

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