M code - Functions: type Function to number

[msksenthil]

Friends, I try to call one function in to the other kind of nested.

M-Code:

let

ADD = (x as any) => let s2 = x+1
in
s2,

SUB = let s33 = ADD -1
in
s33
in
SUB

ERROR:

Thanks in advance

[msksenthil]

@Greg_Deckler @Anonymous Many thanks both of you. The below code is working fine to me

let

ADD = (x as any) => let s2 = x+4
in
s2,

SUB =(x as any) => let s33 = ADD(x) -3
in
s33
in
SUB

[Greg_Deckler]

@msksenthil I would still do it as 2 functions:

let
ADD = (x as any) => let s2 = x+1
in
s2
in
ADD



let
SUB = (x as any) => let s33 = ADD(x)-1
in
s33
in
SUB

[Anonymous]

You need to complete your ADD function. After you have in s2 , you have to write in ADD. right now, ADD is unevaluated function -1. 

[Greg_Deckler]

@msksenthil Perhaps I'm mistaken but don't you want 2 separate functions:

let
ADD = (x as any) => let s2 = x+1
in
s2
in
ADD



let
SUB = (x as any) => let s33 = x+1
in
s33
in
SUB

[msksenthil]

Nope, I try to use the result of the previous 'let' in the following 'let'

[Anonymous]

Instead of "in s2", try "in s2 in ADD".

--Nate

[msksenthil]

Sorry, I didn't get you