How to count values of columns???

[huynq]

Hi everyone, I'm sorry for my bad English. I've tried to find the solution for this but didn't work so I post this message for your help.

I have this data:

A  B  C  D

a  b  c  d

a  b  a  a

c  a  d  o

What I'm looking for
     A  B  C  D
a   2  1  1  1

b   0  2  0  0

c   1  0  1  0

d   0  0  1  1

o   0  0  0  1

I would like to say thanks in advance. 

[Jimmy801 · Accepted solution]

Hello @huynq 

this involves some unpivoting, grouping and pivoting. Check out this code example

let
	Source = #table 
	(
		{ "A", "B", "C", "D" },
		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
	),
	Unpivot = Table.UnpivotOtherColumns 
	(
		Source,
		{ },
		"Attribute",
		"Value" 
	),
	Group = Table.Group 
	(
		Unpivot,
		{ "Attribute", "Value" },
		{ { "Count", each Table.RowCount ( _ ), type number } } 
	),
	Pivot = Table.Pivot 
	(
		Group,
		List.Distinct 
		(
			Group [ Attribute ] 
		),
		"Attribute",
		"Count",
		List.Sum 
	)
 in 
	Pivot

Copy paste this code to the advanced editor in a new blank query to see how the solution works. If this solution fits your need, copy and past a part of it and implement it in your query, or I could create a custom function what makes it easier to apply if you are not used that much to power query.

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[Jimmy801 · Accepted solution]

Hello @huynq 

this involves some unpivoting, grouping and pivoting. Check out this code example

let
	Source = #table 
	(
		{ "A", "B", "C", "D" },
		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
	),
	Unpivot = Table.UnpivotOtherColumns 
	(
		Source,
		{ },
		"Attribute",
		"Value" 
	),
	Group = Table.Group 
	(
		Unpivot,
		{ "Attribute", "Value" },
		{ { "Count", each Table.RowCount ( _ ), type number } } 
	),
	Pivot = Table.Pivot 
	(
		Group,
		List.Distinct 
		(
			Group [ Attribute ] 
		),
		"Attribute",
		"Count",
		List.Sum 
	)
 in 
	Pivot

Copy paste this code to the advanced editor in a new blank query to see how the solution works. If this solution fits your need, copy and past a part of it and implement it in your query, or I could create a custom function what makes it easier to apply if you are not used that much to power query.

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[huynq]

You are the life savior, by the way how can I replace null value by 0? 

[Jimmy801 · Accepted solution]

Hello @huynq 

just use this code instead

let
	Source = #table 
	(
		{ "A", "B", "C", "D" },
		{ { "a", "b", "c", "d" }, { "a", "b", "a", "a" }, { "c", "a", "d", "o" } } 
	),
	Unpivot = Table.UnpivotOtherColumns 
	(
		Source,
		{ },
		"Attribute",
		"Value" 
	),
	Group = Table.Group 
	(
		Unpivot,
		{ "Attribute", "Value" },
		{ { "Count", each Table.RowCount ( _ ), type number } } 
	),
	Pivot = Table.Pivot 
	(
		Group,
		List.Distinct 
		(
			Group [ Attribute ] 
		),
		"Attribute",
		"Count",
		each if List.IsEmpty(_) then 0 else List.Sum (_)
	)
 in 
	Pivot

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[huynq]

@Jimmy801 Bingo, this is what I need. Thank you very much.