Forum Discussion

Cami's avatar
Cami
Frequent Visitor
5 years ago
Solved

How to Parse and Extrat data from column using delimiter

Hi,

 

I have the following Input table(see pic below) and I'd like to have it in the format shown in Output table. How do I parse the column FruitsQuantity taking into account there can the N occurences(\Fruit\Quantity) per person.

 Thanks!

  • Hello Cami 

     

    check out this solution. It's dynamically

     

    let
        Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("LYy9CoAgGEXf5ZsdUqvdKQgChzavg4RU4B9G759Iyx3OOVxjiBOjPce2gColeGAEtHcVmMgyQ6I5Fe7D90aHNwJ86Eo2tOYrdbNUV/wDCGBz6czA/F82KMnaDw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, Name = _t, FruitsQuantity = _t]),
        #"Changed Type" = Table.TransformColumnTypes(Source,{{"ID", Int64.Type}, {"Name", type text}, {"FruitsQuantity", type text}}),
        TransformTextWIthSplitterToTable = Table.TransformColumns
        (
            #"Changed Type",
            {
                {
                    "FruitsQuantity",
                    each Table.FromRecords(List.Transform(List.Split(Text.SplitAny(Text.End(_,Text.Length(_)-1),"\"),2), each [Fruit= _{0}, Quantity= _{1}]))
                }
            }
        ),
        Expand = Table.ExpandTableColumn(TransformTextWIthSplitterToTable, "FruitsQuantity", {"Fruit", "Quantity"}, {"Fruit", "Quantity"})
    in
        Expand

     

     

     

    Copy paste this code to the advanced editor in a new blank query to see how the solution works.


    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

6 Replies

  • Jimmy801's avatar
    Jimmy801
    Community Champion

    Hello Cami 

     

    check out this solution. It's dynamically

     

    let
        Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("LYy9CoAgGEXf5ZsdUqvdKQgChzavg4RU4B9G759Iyx3OOVxjiBOjPce2gColeGAEtHcVmMgyQ6I5Fe7D90aHNwJ86Eo2tOYrdbNUV/wDCGBz6czA/F82KMnaDw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, Name = _t, FruitsQuantity = _t]),
        #"Changed Type" = Table.TransformColumnTypes(Source,{{"ID", Int64.Type}, {"Name", type text}, {"FruitsQuantity", type text}}),
        TransformTextWIthSplitterToTable = Table.TransformColumns
        (
            #"Changed Type",
            {
                {
                    "FruitsQuantity",
                    each Table.FromRecords(List.Transform(List.Split(Text.SplitAny(Text.End(_,Text.Length(_)-1),"\"),2), each [Fruit= _{0}, Quantity= _{1}]))
                }
            }
        ),
        Expand = Table.ExpandTableColumn(TransformTextWIthSplitterToTable, "FruitsQuantity", {"Fruit", "Quantity"}, {"Fruit", "Quantity"})
    in
        Expand

     

     

     

    Copy paste this code to the advanced editor in a new blank query to see how the solution works.


    If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
    Kudoes are nice too

    Have fun

    Jimmy

    • Cami's avatar
      Cami
      Frequent Visitor

      This very much solves my problem.

      Great approach, thanks a lot!

  • Greg_Deckler's avatar
    Greg_Deckler
    Community Champion

    Cami Well, first you would Split by Delimiter:

    After that, probably an unpivot and then you do something where you number each row 1 and 2 and do some fancy stuff. ImkeF edhans 

     

    • Cami's avatar
      Cami
      Frequent Visitor

      Thank you for your quick response!

       

      This does not solve my problem. I need the solution to be dynamic. Split by Delimiter takes into account the maximum number of occurences of the given delimiter from the column and proposes the number of columns to split to. In an environment I could have 6 occurences and in another 10.

       

  • Anonymous's avatar
    Anonymous
    Not applicable

    t

    let
        Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("HYtLCoAgEIbvMms3RhGdxd/FOIgFPgal+ze0/R4hEDOTI1atGdiBluvowEHRBUopmdT6NpN++5mIGCuT9c4LOG3hXgZwAZrnesRSTzF+", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [name = _t, #"fr/qty" = _t]),
        #"Added Custom" = Table.AddColumn(Source, "Custom", each let lst=Text.Split([#"fr/qty"],"\") in  List.Zip({List.Alternate(lst,1,1,1),List.Alternate(lst,1,1,0)})),
        #"Expanded Custom" = Table.ExpandListColumn(#"Added Custom", "Custom"),
        #"Extracted Values" = Table.TransformColumns(#"Expanded Custom", {"Custom", each Text.Combine(List.Transform(_, Text.From), ";"), type text}),
        #"Split Column by Delimiter" = Table.SplitColumn(#"Extracted Values", "Custom", Splitter.SplitTextByDelimiter(";", QuoteStyle.Csv), {"Custom.1", "Custom.2"})
    in
        #"Split Column by Delimiter"

    ry also this:

     

     

    • Anonymous's avatar
      Anonymous
      Not applicable

      another way

       

       

      let
          Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("HYtLCoAgEIbvMms3RhGdxd/FOIgFPgal+ze0/R4hEDOTI1atGdiBluvowEHRBUopmdT6NpN++5mIGCuT9c4LOG3hXgZwAZrnesRSTzF+", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [name = _t, #"fr/qty" = _t]),
          #"Added Custom1" = Table.AddColumn(Source, "Custom.1", each Splitter.SplitTextByCharacterTransition( {"0".."9"},{"\"})([#"fr/qty"])),
          #"Expanded Custom.1" = Table.ExpandListColumn(#"Added Custom1", "Custom.1"),
          #"Split Column by Character Transition" = Table.SplitColumn(#"Expanded Custom.1", "Custom.1", Splitter.SplitTextByCharacterTransition({"\"}, {"0".."9"}), {"fruits", "quantity"}),
          #"Replaced Value" = Table.ReplaceValue(#"Split Column by Character Transition","\","",Replacer.ReplaceText,{"fruits"})
      in
          #"Replaced Value"