Forum Discussion
How to Parse and Extrat data from column using delimiter
- 5 years ago
Hello Cami
check out this solution. It's dynamically
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("LYy9CoAgGEXf5ZsdUqvdKQgChzavg4RU4B9G759Iyx3OOVxjiBOjPce2gColeGAEtHcVmMgyQ6I5Fe7D90aHNwJ86Eo2tOYrdbNUV/wDCGBz6czA/F82KMnaDw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, Name = _t, FruitsQuantity = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"ID", Int64.Type}, {"Name", type text}, {"FruitsQuantity", type text}}), TransformTextWIthSplitterToTable = Table.TransformColumns ( #"Changed Type", { { "FruitsQuantity", each Table.FromRecords(List.Transform(List.Split(Text.SplitAny(Text.End(_,Text.Length(_)-1),"\"),2), each [Fruit= _{0}, Quantity= _{1}])) } } ), Expand = Table.ExpandTableColumn(TransformTextWIthSplitterToTable, "FruitsQuantity", {"Fruit", "Quantity"}, {"Fruit", "Quantity"}) in ExpandCopy paste this code to the advanced editor in a new blank query to see how the solution works.
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Kudoes are nice too
Have fun
Jimmy
Cami Well, first you would Split by Delimiter:
After that, probably an unpivot and then you do something where you number each row 1 and 2 and do some fancy stuff. ImkeF edhans
- Cami5 years agoFrequent Visitor
Thank you for your quick response!
This does not solve my problem. I need the solution to be dynamic. Split by Delimiter takes into account the maximum number of occurences of the given delimiter from the column and proposes the number of columns to split to. In an environment I could have 6 occurences and in another 10.