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Mederic
Post Patron
2 years ago
Solved

Fill a column with identical labels

Hello everyone,
I have a column with a number of nested data that repeat every 5 values
How do I get a column with label names? (see screenshot)

Thanks in advance

Best Regards

 

Input
James
M
A213
19/05/1994
London
Maria
F
B623
28/06/1974
Paris
Anthony
M
A931
21/09/1983
Berlin

 

 

  • Here's one way:

    let
        Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45W8krMTS1WitWJVvIFk45GhsZghqGlvoGpvqGlpQmY65Ofl5KfB1GYWJSZCGa5gUknMyOIFiMLfQMzoBZziJYAoDqI0Y55JRn5eZXI1lgaG0L0GOobWAL1WECMcEotyskEWhMLAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Input = _t]),
        #"Changed Type" = Table.TransformColumnTypes(Source,{{"Input", type text}}),
    
        Labels = {"Name","Gender","ID","Birth","City"},
        #"Label Column" = List.Repeat(Labels,Table.RowCount(#"Changed Type")/5),
    
        #"Add Label Column" = Table.FromColumns(
            Table.ToColumns(#"Changed Type") & 
            {#"Label Column"}, Table.ColumnNames(#"Changed Type") & {"Result"}),
    
        #"Changed Type1" = Table.TransformColumnTypes(#"Add Label Column",{{"Result", type text}})
    in
        #"Changed Type1"

     

     

2 Replies

  • Here's one way:

    let
        Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45W8krMTS1WitWJVvIFk45GhsZghqGlvoGpvqGlpQmY65Ofl5KfB1GYWJSZCGa5gUknMyOIFiMLfQMzoBZziJYAoDqI0Y55JRn5eZXI1lgaG0L0GOobWAL1WECMcEotyskEWhMLAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Input = _t]),
        #"Changed Type" = Table.TransformColumnTypes(Source,{{"Input", type text}}),
    
        Labels = {"Name","Gender","ID","Birth","City"},
        #"Label Column" = List.Repeat(Labels,Table.RowCount(#"Changed Type")/5),
    
        #"Add Label Column" = Table.FromColumns(
            Table.ToColumns(#"Changed Type") & 
            {#"Label Column"}, Table.ColumnNames(#"Changed Type") & {"Result"}),
    
        #"Changed Type1" = Table.TransformColumnTypes(#"Add Label Column",{{"Result", type text}})
    in
        #"Changed Type1"

     

     

  • Hello ronrsnfld ,

    Thank you very much, it worked perfectly as always ğŸ™‚
    Have a nice day