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borstroem
Regular Visitor

Count columns which contain text

Hi

 

I'm looking to create a new column which counts the columns which contains any text in that given row. Example:

 

IDXYZCells with text
1AppleOrangeBanana3
2BananaApple 2
3 Banana 1
4   0
5  Apple1
6OrangeApple 2

 

I guess I'm looking for a M equivalent of the excel function countif(row, "*")

 

Thanks a lot in advance 🙂

 

 

1 ACCEPTED SOLUTION
serpiva64
Solution Sage
Solution Sage

Hi,

you can obtain this

serpiva64_0-1675352411415.png

by applying the steps of the attached file

If this post is useful to help you to solve your issue, consider giving the post a thumbs up and accepting it as a solution!

View solution in original post

2 REPLIES 2
latimeria
Solution Specialist
Solution Specialist

Hi @borstroem ,

 

Another way, using list

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUXIsKMhJBdL+RYl56SCGU2IeECrF6kQrGSG4CIVgGWMQA0kSLGgCEYRxTeFciFaQmBmyTQgTYwE=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, X = _t, Y = _t, Z = _t]),
    #"Replaced Value" = Table.ReplaceValue(Source,"",null,Replacer.ReplaceValue,{"Z"}),
    #"Added Custom" = Table.AddColumn(#"Replaced Value", "Custom", each List.Count(List.Select(List.Skip(Record.ToList(_),1), each _ <> "" and _ <> null )))
in
    #"Added Custom"
serpiva64
Solution Sage
Solution Sage

Hi,

you can obtain this

serpiva64_0-1675352411415.png

by applying the steps of the attached file

If this post is useful to help you to solve your issue, consider giving the post a thumbs up and accepting it as a solution!

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