Calculate cumulative reverse

[danilomorganti]

Hello guys!

I need your help about a reverse cumulative formula. I get data from file with the cumulative of value and I would like to decompose this value with day-by-day value. How can I do it?

Source data is like this

Date	Cumulative
01/01/2021	0
02/01/2021	10
03/01/2021	15
04/01/2021	23
05/01/2021	34
06/01/2021	56
07/01/2021	78
08/01/2021	85

And I would like to automatically calculate the single day value in the same month, the result should this

Date	Cumulative	Result
01/01/2021	0	0
02/01/2021	10	10
03/01/2021	15	5
04/01/2021	23	8
05/01/2021	34	11
06/01/2021	56	22
07/01/2021	78	22
08/01/2021	85	7

Could someone help me?

Thank you so much!

[Jimmy801 · Accepted solution]

Hello @danilomorganti 

you can try this approach but it doesn't look on the date but really on the prior cell value. It basically adds a new column with the cumulative-column but shifted down by one row. After that a new column is added where your needed calculation takes place

Here a code example

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("Tc27DQAhDATRXhwjnT8Y3Aui/zbO0hKsNNFL5hxR+zpXNxmickeTE9mzYEvYJPOAJVlM2CLLBdtku2BFVv24Pw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Date = _t, Cumulative = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Date", type date}, {"Cumulative", Int64.Type}}),
    GetNewColumnWithPreviousValue = Table.FromColumns
    (
        Table.ToColumns(#"Changed Type")&{{0}&List.RemoveLastN(#"Changed Type"[Cumulative])},
        Table.ColumnNames(#"Changed Type")&{"CumulativeShifted"}
    ),
    #"Added Custom" = Table.AddColumn(GetNewColumnWithPreviousValue, "Result", each [Cumulative]-[CumulativeShifted]),
    #"Removed Columns" = Table.RemoveColumns(#"Added Custom",{"CumulativeShifted"})
in
    #"Removed Columns"

Result

Copy paste this code to the advanced editor in a new blank query to see how the solution works.

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy

[Jimmy801]

Hello @danilomorganti 

did some replies help you solving the problem?

BR

Jimmy

[v-alq-msft · Accepted solution]

Hi, @danilomorganti 

Based on your description, I created data to reproduce your scenario. The pbix file is attached in the end.

Table:

You may create a custom column as below.

let
tab=Table.SelectRows(#"Changed Type",(x)=>Date.Month(x[Date])=Date.Month([Date]) and x[Date]<[Date]),
m=try [Cumulative]-Table.Max(tab,"Date")[Cumulative] otherwise [Cumulative]-0
in 
m

Result:

Best Regards

Allan

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[Jimmy801 · Accepted solution]

Hello @danilomorganti 

you can try this approach but it doesn't look on the date but really on the prior cell value. It basically adds a new column with the cumulative-column but shifted down by one row. After that a new column is added where your needed calculation takes place

Here a code example

let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("Tc27DQAhDATRXhwjnT8Y3Aui/zbO0hKsNNFL5hxR+zpXNxmickeTE9mzYEvYJPOAJVlM2CLLBdtku2BFVv24Pw==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Date = _t, Cumulative = _t]),
    #"Changed Type" = Table.TransformColumnTypes(Source,{{"Date", type date}, {"Cumulative", Int64.Type}}),
    GetNewColumnWithPreviousValue = Table.FromColumns
    (
        Table.ToColumns(#"Changed Type")&{{0}&List.RemoveLastN(#"Changed Type"[Cumulative])},
        Table.ColumnNames(#"Changed Type")&{"CumulativeShifted"}
    ),
    #"Added Custom" = Table.AddColumn(GetNewColumnWithPreviousValue, "Result", each [Cumulative]-[CumulativeShifted]),
    #"Removed Columns" = Table.RemoveColumns(#"Added Custom",{"CumulativeShifted"})
in
    #"Removed Columns"

Result

Copy paste this code to the advanced editor in a new blank query to see how the solution works.

If this post helps or solves your problem, please mark it as solution (to help other users find useful content and to acknowledge the work of users that helped you)
Kudoes are nice too

Have fun

Jimmy