Forum Discussion
Assigning a value to an ID based on a column with multiple values
- Anonymous2 years ago
Hi dh123
It can also work, the logic is to sort the value by descending , then take the first value, the first value will be the max value
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
- 2 years ago
Hi dh123, try this one:
Result:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUfJJLUvNUTDUUYAwjGAMY6VYnWglI7gKYwwVhmAVxnAVJnAVCCVwhplSbCwA", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, Qualifications = _t]), Ad_LevelNumber = Table.AddColumn(Source, "Level Number", each List.Transform(Text.Split([Qualifications], ","), (x)=> Number.From(Text.Select(Text.From(x), {"0".."9"}))) , type list), Ad_HighestNumberPosition = Table.AddColumn(Ad_LevelNumber, "Highest Number Position", each List.PositionOf([Level Number], List.Max([Level Number])), type number), Ad_HighestLevelOfPosition = Table.AddColumn(Ad_HighestNumberPosition, "Highest level of qualification", each List.Transform(Text.Split([Qualifications], ","), Text.Trim){[Highest Number Position]}, type text), #"Removed Columns" = Table.RemoveColumns(Ad_HighestLevelOfPosition,{"Level Number", "Highest Number Position"}) in #"Removed Columns"
Hi dh123
Create a custom column and try the following code.
List.First(List.Sort(Text.Split(Text.Replace([Qualifications]," ",""),","),Order.Descending))
Output
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi,
Thank you for responding - the issue with this formula is that it only takes the last value in the column but the values are not always in order - it could be level 2, level 3, level 1
- Anonymous2 years agoNot applicable
Hi dh123
It can also work, the logic is to sort the value by descending , then take the first value, the first value will be the max value
Best Regards!
Yolo Zhu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.