March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early bird discount ends December 31.
Register NowBe one of the first to start using Fabric Databases. View on-demand sessions with database experts and the Microsoft product team to learn just how easy it is to get started. Watch now
I have the following input from a text file:
11,1,11,DT:17.09.18/13:04:30
11,2,12,NR:5963
11,3,13,NR:102
11,4,21,NR:200170006
11,4,23,NR:200170000
11,4,24,TX:'1'
11,4,31,CA:1/3.5
11,5,11,DT:17.09.18/16:53:13
11,6,12,NR:5423
11,7,13,NR:5
11,8,21,NR:200010002
11,8,23,NR:200010000
11,8,24,TX:'1'
11,8,31,CA:1/3.8
Column 1: constant (11)
Column 2: consecutive counter
Column 3: row type (e.g. 11 = Date; 12: Key for person; 21: product key; 23: product group key; 31: number of units and revenue
The rows with types 11 always embed a unit of transaction and I'd like to create a new column, which holds an identifier for the transaction. This could be the counter (Col 2) of the date row (Col 3 = 11).
That means, for each row, the value of column 2 of the last previous row of type 11 has to be found. In the above example, the new column would hold 1 for the first seven rows and 5 for the last seven rows.
That's quite easy in DAX, but I'd like to do it on the Power Query level in M.
Any ideas?
Thanks ind advance
Frank
Solved! Go to Solution.
Hi @fbackes,
I think I found a solution for you.
1. Add index column
2. Calculate transaction ID per each row as per below code (see Result step):
let //Entered your data Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjRU0lECY0OlWB0o3wjEN0LwjUF8YwTfBKTGEI2PLm+CyjdGUm+KZp8Zmn3maPZZoNlngWafBZp9FlD7YgE=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [constant = _t, #"consecutive counter" = _t, #"row type" = _t]), ChangedDataTypes = Table.TransformColumnTypes(Source,{{"constant", Int64.Type}, {"consecutive counter", Int64.Type}, {"row type", Int64.Type}}), //Add index starting from zero AddIndexColumn = Table.AddIndexColumn(ChangedDataTypes, "Row", 0, 1), //Calculate transaction id Result = Table.AddColumn(AddIndexColumn, "TransactionID", each let Ix = [Row], value = List.Last(Table.SelectRows(AddIndexColumn,each [Row]<=Ix and [row type] = 11)[consecutive counter]) in value ) in Result
Regards,
Ruslan
-------------------------------------------------------------------
Did I answer your question? Mark my post as a solution!
Hi @fbackes,
I think I found a solution for you.
1. Add index column
2. Calculate transaction ID per each row as per below code (see Result step):
let //Entered your data Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMjRU0lECY0OlWB0o3wjEN0LwjUF8YwTfBKTGEI2PLm+CyjdGUm+KZp8Zmn3maPZZoNlngWafBZp9FlD7YgE=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type text) meta [Serialized.Text = true]) in type table [constant = _t, #"consecutive counter" = _t, #"row type" = _t]), ChangedDataTypes = Table.TransformColumnTypes(Source,{{"constant", Int64.Type}, {"consecutive counter", Int64.Type}, {"row type", Int64.Type}}), //Add index starting from zero AddIndexColumn = Table.AddIndexColumn(ChangedDataTypes, "Row", 0, 1), //Calculate transaction id Result = Table.AddColumn(AddIndexColumn, "TransactionID", each let Ix = [Row], value = List.Last(Table.SelectRows(AddIndexColumn,each [Row]<=Ix and [row type] = 11)[consecutive counter]) in value ) in Result
Regards,
Ruslan
-------------------------------------------------------------------
Did I answer your question? Mark my post as a solution!
Many thanks, Ruslan! It works perfect.
Best regards
Frank
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount!
Your insights matter. That’s why we created a quick survey to learn about your experience finding answers to technical questions.
Arun Ulag shares exciting details about the Microsoft Fabric Conference 2025, which will be held in Las Vegas, NV.
User | Count |
---|---|
7 | |
3 | |
2 | |
1 | |
1 |
User | Count |
---|---|
8 | |
3 | |
2 | |
2 | |
2 |