Skip to main content
cancel
Showing results for 
Search instead for 
Did you mean: 

Earn a 50% discount on the DP-600 certification exam by completing the Fabric 30 Days to Learn It challenge.

Reply
PraveenGuntuka
Regular Visitor

filter using two columns

Hi,

 

We have a requirement to filter data based on two column values.

contat

Trade

source

Corporate

Salesperson

123

 $     100

SMS

Y

Y

242

 $     200

ETF

N

Y

123

 $     300

PPM

N

Y

456

 $     400

DATABREAK

Y

N

789

 $     500

SMS

Y

Y

234

 $     600

ETF

N

Y

457

 $     700

PPM

N

Y

678

 $     800

DATABREAK

Y

N

 

 

Create a formula or parameter with Corporate and Salesperson names. When Corporate is selected, report should display all the “Y” values from the Corporate column and if “Salesperson” is selected all the “Y” values from Salesperson column should display.

 

report should use single slicer /parameter to filter the data.

1 ACCEPTED SOLUTION
PraveenGuntuka
Regular Visitor

it would probably make sense to calculate a new table to handle this. The table will have two columns, Corporate and SalesPerson :

Slicer Table =
UNION (
SELECTCOLUMNS (
FILTER( 'Table' , 'Table'[Corporate] <> BLANK() ) ,
"Source" , 'Table'[Source] ,
"Selection" , 'Table'[Corporate]
),
SELECTCOLUMNS (
FILTER ( 'Table' , 'Table'[Salesperson] <> BLANK() ) ,
"Source" , 'Table'[Source] ,
"Selection" , 'Table'[SalesPerson]
)
)
After this has been calculated, create a relationship between these tables, between the Source columns. Since this is purely for filtering the table on the person of interest, make it be Many-to-Many and have Slicer Table filter Table:


Create a slicer with the Selection column from the Slicer Table and test the functionality:

View solution in original post

5 REPLIES 5
Syndicate_Admin
Administrator
Administrator

Good afternoon! I need to know the total amount I have of "Yes, "TRUE", "yes" in the RESTULT column. STATUS. For this, you need to filter the column, how? After that I need to use a measure to know the amount I have of "Yes, "TRUE", "yes".

image.jpg

Hi,

If you wish to count the Yes/true in the Result column, then write this measure

Measure = calculate(countrows(Data),Data[Result]="Yes"||Data[Result]="true")

My assumption is that true is text true (not a boolean true).

Hope this helps.


Regards,
Ashish Mathur
http://www.ashishmathur.com
https://www.linkedin.com/in/excelenthusiasts/
PraveenGuntuka
Regular Visitor

it would probably make sense to calculate a new table to handle this. The table will have two columns, Corporate and SalesPerson :

Slicer Table =
UNION (
SELECTCOLUMNS (
FILTER( 'Table' , 'Table'[Corporate] <> BLANK() ) ,
"Source" , 'Table'[Source] ,
"Selection" , 'Table'[Corporate]
),
SELECTCOLUMNS (
FILTER ( 'Table' , 'Table'[Salesperson] <> BLANK() ) ,
"Source" , 'Table'[Source] ,
"Selection" , 'Table'[SalesPerson]
)
)
After this has been calculated, create a relationship between these tables, between the Source columns. Since this is purely for filtering the table on the person of interest, make it be Many-to-Many and have Slicer Table filter Table:


Create a slicer with the Selection column from the Slicer Table and test the functionality:

PraveenGuntuka
Regular Visitor

Hi @alekhved 

Requirment to use a single slicer option to filter the data.

alekhved
Resolver I
Resolver I

hi @PraveenGuntuka 

 

Based on problem description it seems like Adding two slicers with these two column should solve the purpose. Am I missing something?

 

Thanks,

alekh

Helpful resources

Announcements
RTI Forums Carousel3

New forum boards available in Real-Time Intelligence.

Ask questions in Eventhouse and KQL, Eventstream, and Reflex.

MayPowerBICarousel

Fabric Monthly Update - May 2024

Check out the May 2024 Fabric update to learn about new features.

LearnSurvey

Fabric certifications survey

Certification feedback opportunity for the community.