Using ALLEXCEPT on calculated table

[wcd1213]

Hello All,

I have a summarization table that pulls from two different tables in my report. I would like to get the average from other columns split up by name. 

For example I would like to populate the new column I created with the averages of M1 split up by Will. The values that I am gettting are the same for every name. 

Any help is appreciated. 

[v-yanjiang-msft · Accepted solution]

Hi @wcd1213 ,

According to your description, here's my solution. Create a calculated column.

Column =
AVERAGEX (
    FILTER (
        'Calculated Table',
        'Calculated Table'[Name] = EARLIER ( 'Calculated Table'[Name] )
    ),
    [M1]
)

Best Regards,
Community Support Team _ kalyj

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[wcd1213]

Hi @v-yanjiang-msft , 

Thank you for the reply.

I tested this expression and the column is not averaging by name. Is there something else I can add to the formula to acheive this?

[v-yanjiang-msft]

Hi @wcd1213 ,

I create a sample and it averages by name as expected.

Do you have some difference with me?

I attach my sample below for your reference.

Best Regards,
Community Support Team _ kalyj

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[wcd1213]

Hi @v-yanjiang-msft ,

I looked at your sample and i used the same expressions. However the table I am working on is summarized from two other tables. 

Here is the expression I used to summarize the columns. 

And here is my expression for getting the average. 

[v-yanjiang-msft]

Hi @wcd1213 ,

According to your snapshot, isn't 4.2857 the average of the name Will? If not, what the 4.2857 really is.

I recreate a sample like you, and it still get the correct result.

You can download my sample below to see the details.

Best Regards,
Community Support Team _ kalyj

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

[wcd1213]

Hi @v-yanjiang-msft 

4.2857 is the average of all of M1. I just realized my screenshot did not include the next name Joe. That average is the same:

I need the averages to be split between names. 

[v-yanjiang-msft]

Hi @wcd1213 ,

To veryfy the result, I calculate it manually.

For Will, sum is 90. The count of Will is 21, so the result of Will is correct(90/21=4.2857).

For Joe, sum is 60. The count of Will is 14, so the result of Will is correct(60/14=4.2857).

For Jim,  the snapshot data is incomplete, so I can't calculate it manually.

As of now, the result is the same for each name is just a coincidence.

Best Regards,
Community Support Team _ kalyj