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wcd1213's avatar
wcd1213
Frequent Visitor
3 years ago
Solved

Using ALLEXCEPT on calculated table

Hello All, I have a summarization table that pulls from two different tables in my report. I would like to get the average from other columns split up by name.  For example I would like to popu...
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  • v-yanjiang-msft's avatar
    v-yanjiang-msft
    3 years ago

    Hi wcd1213 ,

    According to your description, here's my solution. Create a calculated column.

    Column =
AVERAGEX (
    FILTER (
        'Calculated Table',
        'Calculated Table'[Name] = EARLIER ( 'Calculated Table'[Name] )
    ),
    [M1]
)

     

    Best Regards,
    Community Support Team _ kalyj

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

     

v-yanjiang-msft's avatar
v-yanjiang-msft
Community Support
3 years ago

Hi wcd1213 ,

I create a sample and it averages by name as expected.

Do you have some difference with me?

 

I attach my sample below for your reference.

 

Best Regards,
Community Support Team _ kalyj

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

wcd1213's avatar
wcd1213
Frequent Visitor
3 years ago

Hi v-yanjiang-msft ,

I looked at your sample and i used the same expressions. However the table I am working on is summarized from two other tables. 

Here is the expression I used to summarize the columns. 

And here is my expression for getting the average. 

 

 

  • v-yanjiang-msft's avatar
    v-yanjiang-msft
    Community Support
    3 years ago

    Hi wcd1213 ,

    According to your snapshot, isn't 4.2857 the average of the name Will? If not, what the 4.2857 really is.

    I recreate a sample like you, and it still get the correct result.

    You can download my sample below to see the details.

     

    Best Regards,
    Community Support Team _ kalyj

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

    • wcd1213's avatar
      wcd1213
      Frequent Visitor
      3 years ago

      Hi v-yanjiang-msft 

      4.2857 is the average of all of M1. I just realized my screenshot did not include the next name Joe. That average is the same:

      I need the averages to be split between names. 

       

      • v-yanjiang-msft's avatar
        v-yanjiang-msft
        Community Support
        3 years ago

        Hi wcd1213 ,

        To veryfy the result, I calculate it manually.

        For Will, sum is 90. The count of Will is 21, so the result of Will is correct(90/21=4.2857).

        For Joe, sum is 60. The count of Will is 14, so the result of Will is correct(60/14=4.2857).

        For Jim,  the snapshot data is incomplete, so I can't calculate it manually.

        As of now, the result is the same for each name is just a coincidence.

         

        Best Regards,
        Community Support Team _ kalyj