Total vendor Value but with filters

[arnoutdt]

Hello all,

I want to create 'vendor buckets' based on their value. This I already arranged; that for a certain vendor I see the bucket where it belongs to.

In my master data I have created vendor buckets that checks these to total vendor value and independent vendor buckets. 

However, creating the following

Total Vendor Value = summarize(Masterdata;Masterdata[Vendor number];"Total Vendor Value";SUM(Masterdata[Value (EUR)]))

it creates buckets on the whole tabel.

I only want to render total vendor value on

- last 12 months

- One Plant; "P010"

- Purchasing groups "110" and "120"

How can I add these constraints to the total vendor value? 

In my master data it looks like;

Vendor buckets = CALCULATE( VALUES(Vendorbuckets[Bucket Name]); FILTER(Vendorbuckets;RELATED('Total Vendor Value'[Total Vendor Value])>= Vendorbuckets[start] && RELATED('Total Vendor Value'[Total Vendor Value]) < Vendorbuckets[end]))

where vendor buckets are fixed values as you can see in the table below.

thank you for helping out!

bucketstotal vendor valuemasterdata

[Anonymous]

HI @arnoutdt,

Please share the sample data for further testing and analysis.

Regards,

Xiaoxin Sheng

[arnoutdt]

I don't see how I can share sample data. 

[Anonymous]

Hi @arnoutdt,

You can upload to onedrive/google drive, then share the file link here.

Regards,

Xiaoxin Sheng

[arnoutdt]

Hello,

Sorry but I can't share this.

how can I add filters to the following?

I have created a table :

Total Vendor Value = summarize(Masterdata;Masterdata[Vendor number];"Total Vendor Value";SUM(Masterdata[Value (EUR)]))

but how can I add some constraints/filters to this value:

Where 

- Plant = P010

much appreciated!

[Anonymous · Accepted solution]

Hi @arnoutdt,

You can add filter function to the table, then use filtered table as the source table of the summarize function.

Total Vendor Value =
SUMMARIZE (
    FILTER ( Masterdata; [Plant] = "P010" );
    [Vendor number];
    "Total Vendor Value"; SUM ( Masterdata[Value (EUR)] )
)

Regards,

Xiaxoin Sheng

[arnoutdt]

thank you!