Forum Discussion
Time format from text
I have to subtract total hours minus the formatted AHT now. I have converted the formatted AHT column in TIME hh:mm: ss format but the Total hour column is getting an error. Further, I converted the total hours to another from 169h 11m 52s and used a similar dax formattedAHT named as TotalTH
For example, the total hours is 169:11:52 which should be minus 1:01:55 which should give output around 168:09:57 approx. but due to a format issue, I cannot get the result. Please review the file for more information - https://drive.google.com/file/d/1ElZARpqQlKEdepanHtZxQXeEw1H7iw8w/view?usp=drivesdk
The difference is more than 24 hours DATE_ENTERED_SR_EST - 09/01/2023 00:19:09 and DATE_CLOSED_UTC_SR - 09/08/2023 01:31:00
The output i am getting is 16:11:52, however, it should be 169:11:52
This is now resolved by below 2 dax's
THF = VAR h= ([DATE_CLOSED_UTC_SR]-[DATE_ENTERED_SR_EST])*24 var hr= ROUNDDOWN(h,0) var m = (h-hr)*60 var mn = ROUNDDOWN(m,0) var s= rounddown((m-mn)*60,0) return format(hr,"00:") & format(mn,"00:") & format (s,"00")
Diff = var t = SUBSTITUTE(SUBSTITUTE(SUBSTITUTE([AHT Text],"h","|"),"m","|"),"s","")
var d = if(PATHLENGTH(t)=3,DIVIDE(value(pathitem(t,1)),24)+DIVIDE(value(pathitem(t,2)),24*60)+DIVIDE(value(pathitem(t,3)),24*60*60),DIVIDE(value(pathitem(t,1)),24*60)+DIVIDE(value(pathitem(t,2)),24*60*60))
VAR h= ([DATE_CLOSED_UTC_SR]-[DATE_ENTERED_SR_EST]-d)*24
var hr= ROUNDDOWN(h,0)
var m = (h-hr)*60
var mn = ROUNDDOWN(m,0)
var s= rounddown((m-mn)*60,0)
return format(hr,"00:") & format(mn,"00:") & format (s,"00")
2 Replies
- ryan_mayuSuper User
time function
hour
A number from 0 to 23 representing the hour.
Any value greater than 23 will be divided by 24 and the remainder will be treated as the hour value.
TIME Function (DAX) | Microsoft Learn
format function
h :Display the hour as a number without a leading zero (0-23).
hh: Display the hour as a number with a leading zero (00-23).FORMAT function (DAX) - DAX | Microsoft Learn
maybe you can change it back to TEXT type
return INT(TotalTimeValue/3600) & ":"&INT(MOD(TotalTimeValue,3600)/60)&":"&INT(MOD(TotalTimeValue,60))
- saud968Memorable Member
This is now resolved by below 2 dax's
THF = VAR h= ([DATE_CLOSED_UTC_SR]-[DATE_ENTERED_SR_EST])*24 var hr= ROUNDDOWN(h,0) var m = (h-hr)*60 var mn = ROUNDDOWN(m,0) var s= rounddown((m-mn)*60,0) return format(hr,"00:") & format(mn,"00:") & format (s,"00")
Diff = var t = SUBSTITUTE(SUBSTITUTE(SUBSTITUTE([AHT Text],"h","|"),"m","|"),"s","")
var d = if(PATHLENGTH(t)=3,DIVIDE(value(pathitem(t,1)),24)+DIVIDE(value(pathitem(t,2)),24*60)+DIVIDE(value(pathitem(t,3)),24*60*60),DIVIDE(value(pathitem(t,1)),24*60)+DIVIDE(value(pathitem(t,2)),24*60*60))
VAR h= ([DATE_CLOSED_UTC_SR]-[DATE_ENTERED_SR_EST]-d)*24
var hr= ROUNDDOWN(h,0)
var m = (h-hr)*60
var mn = ROUNDDOWN(m,0)
var s= rounddown((m-mn)*60,0)
return format(hr,"00:") & format(mn,"00:") & format (s,"00")