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Anonymous's avatar
Anonymous
Not applicable
3 years ago
Solved

Set measure value based on slicer selection

Good afternoon

 

I would be grateful for some help with the following issue.

I have 2 measures Cardcount and Cardpos, which I think I need to make act like two variables and I do not know how.

I need to set each measure to be a value of either "Higher" or "Lower", depending on what I select in a slicer.

I created a table that looks like this

FocusConvPosit
TSR IssueHigherLower
Overall EngagementLowerLower
TSR EngagementLowerHigher
All GoodHigherHigher

 

I created a slicer that uses the values in the Focus column. I created my first measure

FocSel = SELECTEDVALUE(tblFocus[Focus])
Now I want the measure CardCount to equal the value in tblfocus(Conv) and the measure cardpos to equal tblfocus(posit).
 
I then created this measure to try to set the value
Focal =
Switch(
True()
tblfocus[focsel] = "All Good",calculate([cardcount] = "Higher"),
tblfocus[focsel] = "All Good", calculate([cardpos] = "Higher")
etc
)
I tried to use the above as I was unable to make the measures set to the string value.
When I created the measures cardcount and cardpos I used the statement cardcount =""
 
I think i have gone wrong in 
1. I don't know how to use the slicer to set a variable
2. Setting the measure to "" keeps it at a null value
3. refer to point 1
 
I look forward to someone educating me on how to move this along. I am new to this and youtube tutorials are a little hit and miss. I appreciate any guidance.
 
Lola
 
 
Need Help
  • TomMartens's avatar
    TomMartens
    3 years ago

    Hey Anonymous ,

    I have to admit that I do not fully understand what challenges you have to tackle.

     

    No matter, if you are using a slicer based on the column focus you can use this snippet to create two variables in every measure that you want to "react" on the slicer selection

    some measure = 

var selectedConv = SELECTEDVALUE( 'Table'[Conv] , BLANK() ) //provide a default value or consider making the focus slider a single selection
var selectedposit = SELECTEDVALUE( 'Table'[Posit] , BLANK() ) //provide a default value or consider making the focus slider a single selection
return

SWITCH(
    TRUE()
        , selectedConv = "Higher" && selectedposit = "Lower"
            , 1 //put you measure definiton here
        , selectedConv = "Higher" && selectedposit = "Higher"
            , 2
        , selectedConv = "Lower" && selectedposit = "Higher"
            , 3
        , selectedConv = "Lower" && selectedposit = "Lower"
            , 4
)

    You are not restricted to use SELECTEDVALUE with the column that is used on a slicer, the default value is fired when more than one value is selected inside the slicer or none (meaning all).

     

    Hopefully, this provides an idea on how to tackle your challenge.

     

    Regards,

    Tom



2 Replies

  • TomMartens's avatar
    TomMartens
    Super User
    3 years ago

    Hey Anonymous ,

    I have to admit that I do not fully understand what challenges you have to tackle.

     

    No matter, if you are using a slicer based on the column focus you can use this snippet to create two variables in every measure that you want to "react" on the slicer selection

    some measure = 

var selectedConv = SELECTEDVALUE( 'Table'[Conv] , BLANK() ) //provide a default value or consider making the focus slider a single selection
var selectedposit = SELECTEDVALUE( 'Table'[Posit] , BLANK() ) //provide a default value or consider making the focus slider a single selection
return

SWITCH(
    TRUE()
        , selectedConv = "Higher" && selectedposit = "Lower"
            , 1 //put you measure definiton here
        , selectedConv = "Higher" && selectedposit = "Higher"
            , 2
        , selectedConv = "Lower" && selectedposit = "Higher"
            , 3
        , selectedConv = "Lower" && selectedposit = "Lower"
            , 4
)

    You are not restricted to use SELECTEDVALUE with the column that is used on a slicer, the default value is fired when more than one value is selected inside the slicer or none (meaning all).

     

    Hopefully, this provides an idea on how to tackle your challenge.

     

    Regards,

    Tom



    • Anonymous's avatar
      Anonymous
      Not applicable
      3 years ago

      TomMartens 

       

      Thank you so much for this. It was in the ballpark of what I required so I was able to adapt what you had and make it work. I really appreciate it, thank you for your time.