Running count of occurrence of value, sorted by another column

[ebuchholz]

Is there a way I can get a running count based on a reoccuring value in a column, and start a new running count based on new values? Please see the example below for what I am trying to achieve. When defining where to start counting, the data would most likely be sorted by a date column. Thank you!

ID	Desired Output
A	1
A	2
A	3
A	4
A	5
B	1
B	2
B	3
B	4
C	1
C	2
C	3
D	1
D	2
D	3
D	4
E	1
E	2
E	3
E	4
E	5
C	4
A	6
A	7

[Anonymous · Accepted solution]

HI,

If you can add an extra column which is the row number, i.e. 1,2,3,4,5,6... then the following logic should work:

Calculate(COUNTA(Table[ID]), FILTER(Table, Table[ID] = EARLIER(Table[ID]) && Table[Row Number] <= EARLIER(Table[Row Number])))

Essentially, if you are on row 1, A then this will filter your table to just be A's and then any row less than or equal to the current row number and then it will count the number of A's in this filtered table.

So A row 3 will filter the table to just A's and then all rows less than or equal to 3.

Hope this helps,

Will