Forum Discussion
Anonymous
5 years agoNot applicable
PrevRow + index problem
Guys, i'm using dax to get my prev row value based on my index number. First, let's have a look at my table Ok, i need to sort first by my ID number to group all values that are the same, th...
- 5 years ago
Hello @Vieiraguilherme ,
You can create this computed column instead of the index column:
Sort = VAR _rank = RANKX ( FILTER ( ALL ( 'Table' ), 'Table'[ID Number] = EARLIER ( 'Table'[ID Number] ) ), 'Table'[Changed On Timestamp], , ASC, DENSE ) VAR _sort = IF ( [ID Number] = MIN ( 'Table'[ID Number] ), _rank, _rank + CALCULATE ( COUNTROWS ( FILTER ( ALL ( 'Table' ), 'Table'[ID Number] < MAX ( 'Table'[ID Number] ) ) ) ) ) RETURN _sortNext, create a measure to get the previous row:
_prerow = CALCULATE ( MAX ( 'Table'[Changed On Timestamp] ), FILTER ( ALL ( 'Table' ), 'Table'[Sort] = CALCULATE ( MAX ( 'Table'[Sort] ), FILTER ( ALL ( 'Table' ), 'Table'[Sort] < MAX ( 'Table'[Sort] ) ) ) ) )Current Result:
When you add a new row to the table, the value of the previous row is still received successfully:
Attached a sample file in the next one, hopes to help you.
Best Looks,
Yingjie LiIf this post helps, please consider Accepting it as the solution to help the other members find it more quickly.
amitchandak
5 years agoSuper User
Anonymous , Try like
new measure
Acionamento =
CALCULATE(MAX([Changed On Timestamp]),FILTER(table, 'table'[Index] = max( 'table'[Index] )-1))
new column
Acionamento =
CALCULATE(MAX([Changed On Timestamp]),FILTER(table, 'table'[Index] = earlier( 'table'[Index] )-1))