Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
7 years ago
Solved

Network traffic per second

Hello all!

 

I have a question about how to approach a problem I have with a calculation. 

My data looks like the following:

 

TimeSourceAdressDestinationAdressBytes
10:0510.10.10.1099.99.99.9910
10:1011.11.11.1166.66.66.6620
10:1511.11.11.1167.67.67.6710
10:2011.11.11.1166.66.66.6612
10:2512.12.12.1277.77.77.7724
10:3010.10.10.1077.77.77.7730

 

It is connected to a database that updates these fields automatically. Now what I would like to achieve is to calculate how much bytes per seconds/ per minute and per 10 minutes are sent. 

I am not sure how to approach this so it would be greatly appreciated if someone could help/ give me a push in the right direction!

(tips about how to visualise this type of data are also very welcome)

 

Thanks in advance,

L.Meijdam

 

Need Help
  • v-yulgu-msft's avatar
    v-yulgu-msft
    7 years ago

    Hi Anonymous,

     

    Based on my assumption, you could create measures like below, and display results in card visual.

    sent bytes per seconds = SUM(table8[Bytes])/DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),SECOND)
    sent bytes per minute = SUM(table8[Bytes])/DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),MINUTE)
    sent bytes per 10 minutes = SUM(table8[Bytes])/(DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),MINUTE)/10)

    If it doesn't meet your requirement, please provide more description about how to calculate "bytes per seconds/ per minute and per 10 minutes are sent". It would be better you can show desired putput with examples.

     

    Regards,

    Yuliana Gu

4 Replies

  • v-yulgu-msft's avatar
    v-yulgu-msft
    Microsoft Employee
    7 years ago

    Hi Anonymous,

     

    Based on my assumption, you could create measures like below, and display results in card visual.

    sent bytes per seconds = SUM(table8[Bytes])/DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),SECOND)
    sent bytes per minute = SUM(table8[Bytes])/DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),MINUTE)
    sent bytes per 10 minutes = SUM(table8[Bytes])/(DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),MINUTE)/10)

    If it doesn't meet your requirement, please provide more description about how to calculate "bytes per seconds/ per minute and per 10 minutes are sent". It would be better you can show desired putput with examples.

     

    Regards,

    Yuliana Gu

    • Anonymous's avatar
      Anonymous
      Not applicable
      7 years ago

      Hi v-yulgu-msft,

       

      I am sorry the question was not really clear, however the answer you provided worked perfectly for me!

       

      One small thing I was wondering if the measure "Sent bytes per 10 minutes" shouldnt be like this instead:

      sent bytes per 10 minutes = SUM(table8[Bytes])/(DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),MINUTE)*10)

      Perhaps I misunderstood the measure, but I got the feeling that you would get the result of 1 minute / 10 instead of 10 whole minutes.

       

      Thanks!

       

      Best regards,

      L.Meijdam

       

       

      • v-yulgu-msft's avatar
        v-yulgu-msft
        Microsoft Employee
        7 years ago

        Hi Anonymous,

         

        Yes. As you said, if the result should be 1 minute / 10 instead of 10 whole minutes, the measure should be changed to:

        sent bytes per 10 minutes = SUM(table8[Bytes])/(DATEDIFF(MIN(table8[Time]),MAX(table8[Time]),MINUTE)*10)

         

        Regards,

        Yuliana Gu