Forum Discussion
Anonymous
9 years agoNot applicable
Monthly Percent in a Table
Hello everyone,
I´m having problems with a DAX calculation.
I need to calculate the % of hours that suppose every row per month and person and I have a table like this.
Any help?
Thanks.
Hi Anonymous,
Could you try the formula below to see if it works in your scenario? :smileyhappy:
Task % = VAR currentMonth = MONTH ( MAX ( 'Table2'[Fecha de trabajo] ) ) VAR currentYear = YEAR ( MAX ( 'Table2'[Fecha de trabajo] ) )
VAR currentPerson =
MAX ( 'Table2'[Id_Persona] ) VAR HoursInTask = CALCULATE ( SUM ( 'Table2'[Horas] ), ALLEXCEPT ( Table2, 'Table2'[Id_Proyecto] ) ) VAR AmountHoursPersonInAllTasks = CALCULATE ( SUM ( 'Table2'[Horas] ), FILTER ( ALL ( 'Table2' ), 'Table2'[Id_Persona] = currentPerson && ( MONTH ( 'Table2'[Fecha de trabajo] ) = currentMonth && YEAR ( 'Table2'[Fecha de trabajo] ) = currentYear ) ) ) RETURN DIVIDE ( HoursInTask, AmountHoursPersonInAllTasks )Regards
7 Replies
- Phil_Seamark
Microsoft Employee
Hi Anonymous
Could you please post a mock up of what you expect your result to look like. That will help us fill the gap.
- AnonymousNot applicable
Hello Phil_Seamark,
I need a formula that looks like:
Task% = [Hours in the task]/[Amount of worked Hours in the month of this person in all worked tasks]- Phil_Seamark
Microsoft Employee
Hi Anonymous
This might be getting close
Task % = var HoursInTask = CALCULATE(SUM('Table2'[Horas]),ALLEXCEPT(Table2,'Table2'[Id_Proyecto])) var AmountHoursPersonInAllTasks = CALCULATE( SUM('Table2'[Horas]), FILTER( ALL('Table2'), MONTH('Table2'[Fecha de trabajo])= MONTH(MAX('Table2'[Fecha de trabajo])) && YEAR('Table2'[Fecha de trabajo])= YEAR(MAX('Table2'[Fecha de trabajo])) )) RETURN DIVIDE(HoursInTask,AmountHoursPersonInAllTasks)