March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount! Early bird discount ends December 31.
Register NowBe one of the first to start using Fabric Databases. View on-demand sessions with database experts and the Microsoft product team to learn just how easy it is to get started. Watch now
Hello, I need help to check if the numbers in table 1 are available in table 2 and find out the ones that do not exist in table 2. True / False.
I need this as measure and don't want to create a calculated column,
Table 1
Number |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
10 |
11 |
12 |
13 |
14 |
15 |
Table 2
Number |
1 |
3 |
7 |
8 |
10 |
12 |
13 |
15 |
Result
Number | Result |
1 | TRUE |
2 | FALSE |
3 | TRUE |
4 | FALSE |
5 | FALSE |
6 | FALSE |
7 | TRUE |
8 | TRUE |
9 | FALSE |
10 | TRUE |
11 | FALSE |
12 | TRUE |
13 | TRUE |
14 | FALSE |
15 | TRUE |
Solved! Go to Solution.
Hi, @gauravnarchal ;
Try it.
Result = IF(MAX('Table1'[Number]) in VALUES(Table2[Number]),"TRUE","FALSE")
The final output is shown below:
Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
@v-yalanwu-msft, @MargaritaG, @Tahreem24, @amitchandak
Not to piggyback, but I have an additional question to the above solutions.
Table 1 is an employee roster. (Employee ID, name, work location)
Table 2 is a list of employees who have been audited (Employee ID, name, date audited)
The measures above show me a True/False if an employee appears on Table 2 (the audit list). However, I would like to use a slicer to filter by work location. Currently, my slicer returns the entire list of employees (with the correct True/False result ) instead of only those who are assigned to the sliced/selected work location.
Any ideas?
Hi, @gauravnarchal ;
Try it.
Result = IF(MAX('Table1'[Number]) in VALUES(Table2[Number]),"TRUE","FALSE")
The final output is shown below:
Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hey,
You could write measure like this to get the solution required.
Let me know if this works!
@gauravnarchal Join the both table using relationship. Then create a measure in table 1:
@gauravnarchal , A measure to me used with table 1 Number
Measure = if(isblank(COUNTX(filter(Table1, Table1[Number] in values(Table2[Number])),Table1[Number])), FALSE(),TRUE())
March 31 - April 2, 2025, in Las Vegas, Nevada. Use code MSCUST for a $150 discount!
Your insights matter. That’s why we created a quick survey to learn about your experience finding answers to technical questions.
Arun Ulag shares exciting details about the Microsoft Fabric Conference 2025, which will be held in Las Vegas, NV.
User | Count |
---|---|
132 | |
90 | |
88 | |
64 | |
58 |
User | Count |
---|---|
203 | |
141 | |
107 | |
73 | |
70 |